The COD can be estimated from the concentration of oxidizable compound in the sample, based on its stoichiometric reaction with oxygen to yield CO2 (assume all C goes to CO2), H2O (assume all H goes to H2O), and NH3 (assume all N goes to NH3), using the following formula:COD = (C/FW)(RMO)(32)Where C = Concentration of oxidizable compound in the sample,FW = Formula weight of the oxidizable compound in the sample,RMO = Ratio of the # of moles of oxygen to # of moles of oxidizable compound in their reaction to CO2, water, and ammonia
For example, if a sample has 500 wppm of phenol:C6H5OH + 7O2 → 6CO2 + 3H2OCOD = (500/94)(7)(32) = 1191 wppm
Chlorine will not be seperated out of the sample effluent.
It will be invaluable if (when) you need to calculate sample correlation coefficient, but otherwise, it has pretty much no value.
Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.
It is a value calculated from the sample values only.It is a value calculated from the sample values only.It is a value calculated from the sample values only.It is a value calculated from the sample values only.
in order to calculate the mean of the sample's mean and also to calculate the standard deviation of the sample's
Percent inhibition can be calculated using the formula: % Inhibition = [(Control value - Sample value) / Control value] x 100. First, subtract the sample value from the control value, then divide that result by the control value, and finally multiply by 100 to express it as a percentage.
No. To calculate a sample standard deviation one requires the sample values. The five-number summary provides only the lowest value, the highest, the median, and the upper and lower quartiles. In any sample of size greater than five some values will be missing from the summary.
To calculate the enrichment factor of Zn in soil, you would typically compare the concentration of Zn in the soil sample of interest to a reference value, such as the background Zn concentration in soils. The formula for enrichment factor (EF) is: EF = (Zn sample / Zn background), where Zn sample is the concentration of Zn in the soil sample and Zn background is the reference value. A value of EF greater than 1 indicates enrichment of Zn in the soil compared to the background level.
You can calculate the value of calcium carbonate in limestone by determining the percentage of calcium carbonate present in the sample and then multiplying that by the market price per ton of calcium carbonate. The formula is: Value = (Percentage of calcium carbonate / 100) x Market price per ton.
It means theres a high amount of variation between the results used to calculate the mean value for a particular sample or experiment
COD measures the amount of oxygen required to chemically oxidize (break down) organic and inorganic matter in a water sample, while BOD measures the amount of oxygen consumed by microorganisms during a biological process that breaks down organic matter. COD typically gives a higher value than BOD because it includes both the chemical and biological oxygen demand in the water sample.
We would need to know what sample you are referring to in order to answer this question.