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What is the mass of a boron sample which contains 585 moles of b atoms?
Wiki User
∙ 12y ago
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram Atomic Mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
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∙ 12y ago
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Which sample contains the greatest number of atoms a sample of Mn that contains 3.29E plus 24 atoms or a 5.18 mole sample of you?
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 and times 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To calculate the mass of 1 x 10^6 boron atoms, you divide 6.022 x 10^23 (Avogadro's number) by 1 x 10^6 to find the number of moles, which equals 0.001673 moles. Multiply this by the molar mass of boron to get approximately 0.0181 grams.
Which sample contains the greatest number of atoms a sample of Al that contains 8.18E plus 23 atoms or a 5.16 mole sample of S?
The sample of Al that contains 8.18E+23 atoms has more atoms than a 5.16 mole sample of S. This is because one mole of any substance contains Avogadro's number of atoms or molecules, which is approximately 6.022 x 10^23. Since the Al sample has more atoms than this, it contains the greater number of atoms.
How many atoms are in 4.0 moles of boron?
There are 4.81 x 10^24 atoms in 4.0 moles of boron. This value is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of boron.
How many moles of N2O molecules are present in a sample that contains 5.23 moles of nitrogen atoms?
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 x 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To find the mass of 1 x 10^6 atoms of boron, divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass of boron. Therefore, the mass of 1 x 10^6 boron atoms would be approximately 1 x 10^-5 grams.
What approximate mass would a sample of naturally occurring boron B that contains?
The atomic weight of boron (B) is approximately 10.81 g/mol. To calculate the mass contained in a sample, you need to know the number of moles present and then multiply that by the molar mass of boron.
How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 1024 fluorine atoms?
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
How many moles of fluorine in 3 moles of borontrifluoride?
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
How many moles of carbon atoms can be obtained from the decomposition of C6H6 in a 1.68 moles sample?
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.
How many moles in 31.78G of Boron?
To find the number of moles in 31.78g of Boron, we first need to determine the molar mass of Boron, which is approximately 10.81 g/mol. Then, we can use the formula: Number of moles = Mass (g) / Molar mass. So, for 31.78g of Boron, the number of moles would be 31.78g / 10.81 g/mol = 2.94 moles.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The molar mass of phosphorus is approximately 31 g/mol. To find the number of moles in a 100 g sample, divide the mass by the molar mass: 100 g / 31 g/mol = 3.23 mol. Therefore, there are approximately 3.23 moles of phosphorus atoms in a 100 g sample of phosphorus.
