Sin theta of 30 degrees is1/2
(/) = theta sin 2(/) = 2sin(/)cos(/)
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
The acceleration of a pendulum is directly proportional to the acceleration due to gravity (g). The formula to calculate the acceleration of a pendulum is a = g * sin(theta), where theta is the angle between the pendulum and the vertical line. This means that an increase in g will result in a corresponding increase in the acceleration of the pendulum.
inclined planes can be used in the investigation of acceleration. specificaly using m*g*sin(theta)=a (well i think that was the equation) acceleration is equal to mass*gravity*sin(theta) where sin(theta) is equal to opposite(o) over hypotenuse(h) or theta = (1/sin) * o/h
To plot an Acceleration vs sin theta graph in Microsoft Excel, you first need to have the data for acceleration and sin theta in two columns. Then select the two columns of data, go to the "Insert" tab, choose "Scatter" from the charts group, and then select a scatter plot with data points only. Finally, customize your graph by adding axis labels and a title.
One relationship is: cos(x) = sin(90° - x) if you use degrees. Or in radians: cos(x) = sin(pi/2 - x) Another relationship is the pythagorean identity.
It's 1/2 of sin(2 theta) .
I assume you are asking this in regards to an inclined plane so I will answer it accordingly, Well Recall the equation Force = Mass x Acceleration. In the case of free falling objects Acceleration is equal to gravity, however, on an inclined plan the presence of an incline prevents the object from falling straight down. Instead it must accelerate with some component of gravity. Now recall that perpendicular forces of action on an Incline plane are calculated by Sin theta and that perpendicular forces ( the normal force) is calculated by Cos theta Hence because the object is accelerating down an incline the formula for its total force parallel to the object would be Force = mg sin theta Now if you remember, if you simply remove the mass from the above equation you will be left with the acceleration component of the problem ala the force = mass x acceleration formula. So gsintheta represents A ( acceleration) in the Force = mass times acceleration formula.
The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))
The acceleration of an object on an incline is influenced by the angle of inclination. A steeper incline will result in a greater component of the object's weight acting parallel to the incline, leading to a greater acceleration. The acceleration can be calculated using the formula a = g * sin(theta), where "a" is the acceleration, "g" is the acceleration due to gravity, and "theta" is the angle of inclination.
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
(Sin theta + cos theta)^n= sin n theta + cos n theta