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Q: List of Nigerian past head of states and dates?
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How would you in C programming using a Node struct and a Linkedlist struct take user integer inputs and store them in the linked list in numerical order and then print them in order?

#include<stdio.h> #include<malloc.h> typedef struct linkedlist_node_t { int value; linkedlist_node_t* next; } linkedlist_node; typedef struct linkedlist_t { linkedlist_node* head; } linkedlist; /* Deletes all nodes in the given list. */ void delete_all (linkedlist* list) { /* Ensure the list is non-null. */ if (!list) return; linkedlist_node* old_head; while (list->head) { /* Copy the head pointer. */ old_head = list->head; /* Make its next node the new head. */ list->head = old_head->next; /* Release the old head*/ free (old_head); } /* The list is empty. */ list->head = 0; } /* Inserts the given value into the given linked list. */ linkedlist_node* insert_value (linkedlist* list, int value) { /* Ensure the list is non-null. */ if (!list) return 0; /* Instantiate and initialise a new node. */ linkedlist_node* new_node = malloc (sizeof (linkedlist_node)); new_node->value = value; new_node->next = 0; if (list->head==0) { /* If the list is empty (has no head), the new node becomes the head. */ list->head = new_node; } else if (value<list->head->value) { /* Otherwise, if the value is less than the head's value, insert the new node before the head node. The new node becomes the head. */ new_node->next = list->head; list->head = new_node; } else { /* Otherwise, traverse the list to find the insertion point (the node that comes before the new node). */ linkedlist_node* node = list->head; while (node->next && node->next->value<value) node = node->next; /* Insert the new node immediately after node. */ new_node->next = node->next; node->next = new_node; } /* Return the new node (not essential, but good practice). */ return new_node; } /* Prints the given list. */ void print_list (linkedlist* list) { /* Ensure the list is non-null. */ if (!list) return; /* Traverse the list from the head, printing each node on a new line. */ linkedlist_node* n = list->head; while (n) { printf ("%d\n", n->value); n = n->next; } } /* Test-drive the functions. */ int main() { /* Instantiate and initialise an empty list (no head). */ linkedlist list; list.head = 0; /* Insert values (in descending order). */ for (int v=0; v<10; ++v) insert_value (&list, 10-v); /* Print the list (in ascending order). */ print_list (&list); /* Don't forget to release resources! */ delete_all (&list); return 0; }


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