What does the N represent in VBBN's
This browser is totally bloody useless for mathematical display but...The probability function of the binomial distribution is P(X = r) = (nCr)*p^r*(1-p)^(n-r) where nCr =n!/[r!(n-r)!]Let n -> infinity while np = L, a constant, so that p = L/nthenP(X = r) = lim as n -> infinity of n*(n-1)*...*(n-k+1)/r! * (L/n)^r * (1 - L/n)^(n-r)= lim as n -> infinity of {n^r - O[(n)^(k-1)]}/r! * (L^r/n^r) * (1 - L/n)^(n-r)= lim as n -> infinity of 1/r! * (L^r) * (1 - L/n)^(n-r) (cancelling out n^r and removing O(n)^(r-1) as being insignificantly smaller than the denominator, n^r)= lim as n -> infinity of (L^r) / r! * (1 - L/n)^(n-r)Now lim n -> infinity of (1 - L/n)^n = e^(-L)and lim n -> infinity of (1 - L/n)^r = lim (1 - 0)^r = 1lim as n -> infinity of (1 - L/n)^(n-r) = e^(-L)So P(X = r) = L^r * e^(-L)/r! which is the probability function of the Poisson distribution with parameter L.
No, triang is oo gauge and will connect to ho as long as the track code is OK. But N gauge is much smaller.
E N G L A N D
If l > m and m > n then l > n by the transitive property of inequality.
L comes before N
If the sequence (n) converges to a limit L then, by definition, for any eps>0 there exists a number N such |n-L|N. However if eps=0.5 then whatever value of N we chose we find that whenever n>max{N,L}+1, |n-L|=n-L>1>eps. Proving the first statement false by contradiction.
l is greater than n
Let's suppose the opposite and say that it is rational, so we can write it as a fraction of two natural numbers, where m 1:l/mLet's chose l and m in the way that the fraction l/m will be reduced, i.e, l and m have no common divider.So, according to the supposed, (l/m)2 = nFrom here, l2 = nm2Now we see that l should be dividible by m. But we've chosen l and m in such a way that it couldn't be. Contradiction.So we cannot represent the square of n as a rational fracture.
n is the number of moles.
north
N=l-m