28 horses multiplied by 4 legs each horse equal 112 legs 28 * 4 = 112
There are 18 horses and 14 chickens. How? Horses= 4 legs 18*4=72 Chickens= 2 legs 14*2=28 72+28=100
LOL. you state that at the beginning of your question.... 28
Horses are quadrupeds, so they have 4 legs.
If all were horses there would be 428 legs. The shortfall of 36 legs represents 18 chickens so there are 89 horses.
If all were ducks there would be ony 36 legs. The extra 14 legs must represent 7 horses, which with 11 ducks would have 7 x 4 + 11 x 2 ie 28 + 22 ie 50 legs as stated.
Horses use all four legs.
This can be solved by simultaneous equations: First off number of geese is x, number of horses is y. Therefore x + y is 28 Now geese have 2 legs, horses have 4. We know all of the legs have to equal 78. So: 2x + 4y=78 so if we multiply the top equation by -2 we get -2x -2y = -56 Combining both equations you get 2y = 22, i.e. y=11 horses So then you have 28-11 or 17 geese
There would be a total of 70 legs from 10 horses (4 legs each) and 5 cows (4 legs each).
sea horses don't have legs. they only got on tail.
A horse has 4 legs and 1 head. That is that 1 horse represents 5 of 25 legs and heads.So we can say that there are 5 horses (25÷5).
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