Yes.
1750 2 x 5p x q where p and q are prime numbers. 2 * 5^p * q where p = 3 and q = 7
The sum of -p and -q -
2 x 2 x 3 x 5 x p x p x q x q x q = 60p2q3
If x is a rational number, then x = p/q where p and q are integers and q is non-zero.If division by x is defined, then x cannot be zero so that p is also non-zero.Then, to divide any number by x = p/q, simply multiply the number by q/p.
Consider have x^(p/q) where the base, x, is a whole number. p and q are also whole numbers (q is not 0) so that the exponent, p/q, is a fraction. Then x^(p/q) = (x^p)^(1/q), that is, the qth root of x^p or equivalently, x^(p/q) = [x^(1/q)]^p, that is, the pth power of the qth root of x. For example, 64^(2/3) = 3rd root of 64^2 = 3rd [cube] root of 4096 = 16 or (cube root of 64)^2 = 4^2 = 16. If p/q is negative, the answer is the reciprocal of the answer obtained with positive p/q.
tan x
750 can be written as 2 x 5p x q where p and q are prime numbers. The value of p is 3 and the value of q is 7
The sum of -p and -q -
The sum of -p and -q -
The sum of p and q
p x q pq