s=(a+b+c)/2 inradius = √((s-a)(s-b)(s-c)/s) inradius for 3,4,5 = 1
Real World Road Rules Challenge - 1998 Battle of the Seasons N-A-R-C-I-S-S-I-S-T-I-C 23-5 was released on: USA: 17 October 2012
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Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12
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If the three sides of a triangle are a, b and c, then area = SQRT(s*(s-a)*(s-b)*(s-c)), where s = (a+b+c)/2 So in this case * s = (5 + 7 + 11.4)/2 = 23.4/2 = 11.7 So, * s - a = 11.7 - 5 = 6.7 * s - b = 11.7 - 7 = 4.7 * s - c = 11.7 - 11.4 = 0.3 Therefore..... area = SQRT(11.7 * 6.7 * 4.7 * 0.3) area = SQRT(110.5299) area = 10.51332012258734 Rounded to 1 decimal place... area = 10.5
Yes
stoic
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
S U C K S E S S was created on 2009-09-04.