d = 16t² t = 1 s → d = 16 × 1² = 16 × 1 = 16 ft
In order to come up with an answer, we have to impose a couple of rules: 1). we're trying this on the earth 2). we're ignoring the effects of air 3). it's not moving at the beginning of the 5 seconds ... that's when you drop it from your hand Then the rock falls 400 ft in five seconds. What's really interesting is that it doesn't matter how much it weighs. ALL rocks fall the same distance in 5 seconds.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
An object in free fall will fall approximately 64 feet in 2 seconds.
269 feet
the earth doesnt fall.
American Falls - 176 feet Canadian "Horseshoe" Falls - 167 feet
If the rock falls at 96 feet per second then multiply that by two to find out how far the rock traveled in two seconds which is 192 feet. Subtract 192 from 640 and the answer is 448. Therefore, the rock is 448 feet high after two seconds.
3,212 ft.
If it's falling near the earth's surface, the weight is 27.56 pounds (rounded), regardless of how long or how far it's been falling.
1,100 to 1,300 feet.