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The higher order address bus is not multiplexed with data bus of 8085 because that is the way Intel designed the processor.
Besides, the data bus is only 8 bits and the address bus is 16 bits. If you were to multiplex the whole address bus on the data bus, you would need two T1 (ALE) states, and that would be excess logic. Back to the original answer - that is simply the way Intel designed the processor.
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Difference between 8080 and 8085?
The 8085 has a single +5V power supplyThe 8085 has a multiplexed low order address busThe 8085 has extra single pin interrupts, TRAP, RST7.5, RST6.5, and RST5.5The 8085 has serial I/O pins SID and SODThe 8085 has maskable interrupts and the RIM/SIM instructionThe 8085 includes the functionality of the 8224 clock genereator and 8228 system controllerThe 8085 added several 16 bit operations
How is demultiplexing done in 8085 microprocessor?
it is nothing
How many data lines in 8086?
There are eight datalines, D0 through D7, in the 8085 microprocessor. They are shared, or multiplexed with the eight low order address lines, A0 through A7, and are called AD0 through AD7 on the pinout drawing.
What is the meaning of the term 8085 in microprocessor8085?
The designation 8085 was given by Intel for an updated version of the 8080. The 8085 multiplexed the address bus, freeing up some pins, and Intel included newer functionality. The specific reason for the 5, in 8085, was to indicate that the 8085 operated on a single +5V power supply, unlike the 8080, which needed three power supplies, +5V, -5V, and +12V.
What is higher order address of a 16 bit address?
In the 8085, the high order address is A8-A15. In the 8086/8088, the high order address is A8-A19. (For a 16-bit address, the answer is A8-A15, but the answer above reflects the chosen categories, 8085 and 8086/8088, with the 8086/8088 running in 20-bit mode.) In Windows XP, running in 32-bit mode, the high order address is A8-A31, a 32 bit address.
Explain the need to demultiplex the bus AD7-AD0 in 8085 microprocessor?
The AD0-AD7 lines in an 8085 are multiplexed to reduce the pin count of the IC. Several added features were added to the 8085 from the 8080 design, and Intel did not want to require a larger package.
What do you mean by- 8085 microprocessor?
The 8085 was the next generation of the 8080, providing operation on a single +5V power supply, a multiplexed address/data bus, integration of the system controller and clock generator, new automatically vectored interrupts, a few 16 bit instructions, and serial I/O.
How many Address line of 8085 microprocessor?
There are 20 address lines and 16 data lines in the 8086 microprocessor. The low order 16 address lines are multiplexed with the data lines. Some of the high order address lines are multiplexed with status lines.
How many address bits does 8085 have?
The 8085 has a 16 bit address bus.
What is microprocesser 8085?
microprocessor 8085 is basic 8 bit microprocessor by Intel Corp. it has 64Kb memory and 16 address buses and 8 data buses it has 40 pin ic. 8 address and 8 data buses are multiplexed with each other for reducing the total number of pins from the microprocessor 8085 . it require 5MHz clock frequency for operation. only a crystal which connected easily across two pins of microprocessor can provide this clock.
What is latch in 8085?
· A latch remembers the last state it was told to with another latching signal · A buffer merely strengthens a signal so that it can be fanned out with integrity or drive a heftier device. Any amplifier is a buffer. It outputs a state only as long as the state persists on its input(s).
Draw a schemetic to demultiplex bus ad0-ad7 using any octal latch in 8085 microprocessor?
The 8085 microprocessor is used IC 74LS373 to latch the address of 8085. Basically latch is consists of 8 flip flops. Generally we used D-flip flops (Delay).The clock of these flip flops are connected together and available as a output pin called enable.Working : The address will appear on AD0 AD7 lines. The ALE will go high and forcingEnable = 1. This will make latch enable and ready to work. Before address disappears ALE = 0. This will make latch disable. AD0 - AD7 will now be used as data bus.Hence, AD0 - AD7 (low order) address bus of the 8085 microprocessor is multiplexed (time-shared) with the data bus. The buses need to be demultiplexed.
