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Every processor has an op-code fetch cycle. Otherwise, it would not be able to fetch instructions. In the case of the 8086, the three status lines S2, S1, and S0 will have high, low, and low values to indicate an op-code fetch.

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Q: Why 8086 microprocessor do not have op-code fetch cycle?
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Difference between code segment and data segment of an instruction?

In the 8086/8088 microprocessor, the code segment is used to fetch the opcode and any additional instruction bytes that might be part of the instruction, while the data segment is used to fetch and/or store any operand bytes that the instruction requires to be manipulated.This is in the case of no segment override prefix.


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It is mightily referring to Microprocessor 8086 . I think you saw "8086 microprocessor". The 8086 is nothing it indicates the number of microprocessor same as Digital or analog ic's . 8086 microprocessor has 20 Address buses and 8 data buses which has 1 Mb inbuilt memory for performing several type of airthmatical and logical operation.


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Which microprocessor accepts the program written for 8086 without any changes?