Certainly! Here is a simple program in x86 assembly language to calculate the factorial of a given number:
section .data
number db 5
result dw 1
section .text
global _start
_start:
mov cx, 1
mov ax, 1
calculate_factorial:
cmp cx, byte[number]
jg end_calculation
imul ax, cx
inc cx
jmp calculate_factorial
end_calculation:
mov word[result], ax
; Add code here to display or store the result
; Exit the program
mov eax, 1
xor ebx, ebx
int 0x80
This program initializes the number to calculate the factorial of (in this case, 5) and then iterates through a loop to calculate the factorial using the imul
instruction. The result is stored in the result
variable. You would need to add code to display or store the result as needed.
program that take three decimal number as input and find the largest among them in assembly language
8086 assembly language program to check wether given number is perfect or not
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
kjhk
factorial number Var num= prompt("enter any number "); Var i=1; Var fact=1; for(i=1;i
First of all we will define what factorial is and how to it is calculated.Factional is non negative integer. Notation would be n! It is calculated by multiplying all integers from 1 to n;For example:5! = 1 x 2 x 3 x 4 x 5 = 120.Note: 0! = 1Small C program that illustrates how factorial might be counted:#include int factorial(int num);int main() {int num;printf("Enter number: ");scanf("%d", &num);printf("Factorial: %d\n", factorial(num));return 0;}int factorial(int num) {if (num == 0) {return 1;}return num * factorial(num - 1);}Testing:Enter number: 5Factorial: 120Enter number: 0Factorial: 1
There isn't a reason to write a complete program to do this; in any assembly language just shift the value 1 bit to the left to double it.
int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
#include#includeint a,f,n,sum=0; printf("Enter any number"); scanf("%d",&n); f=1; for(a=1;a<=n;a ); { f=f*a; } for(f=1;f<=n;f ); { sum=sum f; } printf("sumation of factorial numbers :",sum); getch(); }
MVI A, 30h MVI B 20h MUL A,B OUT port1 HLT