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The problem as I understand it is the examinee must pass test 1 and test 2 and test 3. Therefore, the probability of passing all 3 exams is .8*.8*.8 = 0.512.
qualitative
No, it is not true.
to 1 significant digit: 8000 2 significant digits: 7700 3 significant digits: 7660 4 significant digits: 7656. 5 significant digits: 7656.0 6 significant digits: 7656.00 and so on and so forth for forever..........
1 significant figure.