Wiki User
∙ 13y agoIt's 75/120 and the answer is in amps.
Wiki User
∙ 9y agoTo light up, the bulb needs an electrical current flowing through it. This current is typically provided by connecting the bulb to a power source, such as a battery or outlet. Once the current flows through the bulb's filament, it heats up and produces light.
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
0.8A
0.8A
Current = (voltage) / (resistance) = 100/130 = 0.769 A = 769 milliamperes (rounded)
im not sure if this will work or not but... If you use a 9v battery threw an inverter, then a step-up transformer to convert 9v DC to 120v ac i think it will light the bulb, however current decreases when you do that and i dont know how much a light bulb needs..worth a try, i might actually try it now
It can, but if you're wanting to run a 120v light bulb on DC, you'll need 120v DC to get the rated output. That's a lot of batteries. It's easier, and more sensible, to find a DC rated light bulb, such as an RV bulb.
What specifically are you wiring? A light bulb would operate dim, a motor will burn up. The current increases thereby requiring larger wire and current protection.
Off hand no but your explanations are not clear as to who is doing what to whom,,
There is no practical difference between a 120V bulb and a 110V bulb. Both are designed to work with the standard voltage in most household electrical systems, which is 120V in the US. The slight variation in voltage is within the acceptable tolerance range for most light bulbs.
A 65-watt light bulb operating at 120 volts draws approximately 0.54 amps of current. You can calculate this by dividing the wattage (65 watts) by the voltage (120 volts) to get the amperage.
To power a 14 volt bulb from a 120 volt outlet, you can use a resistor with a value of around 820 ohms to limit the current and avoid damaging the bulb. This calculation is based on Ohm's Law (V=IR), where V is the voltage drop across the resistor (120V - 14V), and I is the current flowing through the circuit.