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"BYF" is an abbreviation for "Bring Your Friends."

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Maker's code, indicating that the pistol was made by Mauser.

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100-1000 USD depending on specifics

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that should be 'byf 41 and that means it was made by Mauser. value depends on overall condtion................

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value depends on overall condition. your mauser COULD be worth $900-$1200

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no, just means gun made early 1941 (based on serial number)

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Current value is an extended stay in a prison if you are caught with it. Get a lawyer and find out how to get the serial number lifted or restamped.

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look on top by the date. you will see letters. those letters tell you who made the rifle. example 'byf' was made by the mauser factory.........................

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It depends if the parts are all original, if it is beat up and if it was ever restored. Normally, collectors don't like restored guns. It also depends on the person you're selling it to.

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The mutual gravitational attraction.

The attractive gravitational force F between two point masses m1 and m2 a distance r apart is given by

F = Gm1m2 / r2,

where G is Newton's gravitational constant.

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beffore we can answer that question,we must have the code on your p-38.It may say have a ac 43.or byf 42,or cyq 44 code.this will tell what factory made your p-38 and then with the serial number we can tell what year and month it was made.

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The Date is located on the slide of the pistol. Look for a code such as "AC41" or "BYF40". The alpha characters are the manufacturer's codes, and the two-digit numbers are the years (i.e. 41=1941). I think AC is Walther and BYF is Mauser.

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You could be looking at anywhere from $300 to over $1000, dependent on the markings, overall condition, which factory it was manufactured in... however, the ones worth over $1000 are going to be very few and far between, and $300 - $700 is a bit more realistic.

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There is 2 possable manufactures of your P-38 war time pistol.If your P-38 has a byf code then it was made by Mauser Werke,Obendorf am Necker in March/april 1944.If your P-38 has a cyq code then it was produced by Spreewerke of spandau berlin in june 1944.Both of these manufactures had serial numbers with a R suffix.

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Most German wartime pistols and rifles were manufactured in 'blocks" of around 10,000. They would then proceed to the next letter. There could be two blocks of the same letter made in different years.

You should have a manufacturer's code on the pistol like AC (Walther) or BYF (Mauser) and the year made after it. Such as BYF43. Look for these codes to get your info and go from there.

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ok let this immature guy go if he is rude and talks about you behind your back he's not worth your time and you are better than that.

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It's actually a nickname for some of the last lugers made for the German military, although not exactly accurate, lol. In order to complete the last order of lugers while the tooling was being set up, some of the lugers between 1940-42 were fitted with black grips, a black platic bottom for the magazine, and of course, the whole pistol was blued to speed production. History for ya!

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About 150,000 p.38 pistols were produced by Mauser in 1944. If it is a dual tone(barrel is blue and the rest is phosphate green) it is worth up to about $1200 if it's in great shape. If it all blue it is worth $300-800 depending on condition. Condition means a lot as to the price. Also if the major parts of the pistol do not have the same serial number, the price is greatly reduced

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To correctly answer this, I think you need to know three pieces of data that is stamped on the gun:

1: Date of manufacture

2: 3-Letter Supplier Code. ex: "byf"

3: Serial Number -- as long as this is the serial number on the major part of the gun. Some guns are assembled from various parts of other guns and the serial numbers will not match. If they do match, then the last 2-digits will be stamped on several of the parts.

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Your Mauser model 98K should have a series of numbers on the top of the receiver ring such as 137 and below 1938 etc.if it is a early rifle.After 1940 these were marked with a series of letters on top and the last 2 digits of the year of production,such as byf then 41.A appraisal cannot be done without you providing a detailed description of the rifles overall condition including the bore,and if all numbers match on the parts of the rifle or not.

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$600.00 on average .

A Russian rebuilt P-38 byf/43 with a second stamped serial number or a mismathced non-rebuilt goes for about $400.00. In absolute excellent condition it can go for $675.00. If your dad used this or got if off a German who had been using it in combat the gun would not qualify for this "excellent" condition.

The P-38 was developed to replace the "Luger" P-.09 because it was a cheaper gun to manufacture. The "cheapness" and the fact that "Lugers" have a nostalgia make the P-38 a less desirable and therefore less valuable gun. However, as a handgun it may be superior, but most people don't buy them for use so they are a collectable(technology surpassed the P-.09 and the P-38 in the early 1960s although police issues of the P-38 continued until 1995).

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yes. you can it just dose not tast as nice.

You get

1 cup Icing Sugar

I tsp Citric Acid

1 tsp Tartic Acid

1 tsp Baking Soda

2 tsp Raro

Mix all together.

To be enjoyed mix it with water or fruit juice, to make a fizzy drink. If you want to just keep it a powder to make it a treat :3 haha.

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The "byf" marking indicates your P38 was actually made by Mauser. Serial numbers ran in blocks of 10000. After the number 10000 was reached the number sequence was repeated but with an "a" suffix added. Subsequently when each block of 10000 was completed the suffix incremented to the next letter, "b", "c", "d", etc. Your suffix is "p". The "43" normally would mean the pistol was made in 1943, however your serial number implies the pistol was made in January 1944, apparently with a leftover 43 dated slide.

You have not provided enough information to give an accurate opinion of value. Does it have matching serial numbers? Has it been reblued? Condition is all important when considering value. Some use the grading scale of excellent, very good, good, fair and poor. Assuming yours is "good", that is has matching serial numbers and original finish, I would speculate your's may be worth in the neighborhood of $450 to $500.

If you would like a more comprehensive opinion on value, I suggest you post your question with pictures on p38forum.com.

Best regards

Marc

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I suppose you're talking about small wavelenght or large wavelength. In this case, the answer is that a wave with lower wavelenght has more energy than a wave with higher wavelenght.

You have to consider that the energy associated to an electromagnetic wave is, according to de Broglie:

E = hf

where h is the Planck constant (which is, more or less, h = 6.626·10-34 Js) and f is the frequency of the wave. The relationship between frequency and wavelenght is given by

f = c/lambda

where c is the speed of light and lambda the wavelenght. So finally you have

E = hc/lambda

According to this equation, the higher the wavelenght, the lower the energy.

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I suppose you're talking about small wavelenght or large wavelength. In this case, the answer is that a wave with lower wavelenght has more energy than a wave with higher wavelenght.

You have to consider that the energy associated to an electromagnetic wave is, according to de Broglie:

E = hf

where h is the Planck constant (which is, more or less, h = 6.626·10-34 Js) and f is the frequency of the wave. The relationship between frequency and wavelenght is given by

f = c/lambda

where c is the speed of light and lambda the wavelenght. So finally you have

E = hc/lambda

According to this equation, the higher the wavelenght, the lower the energy.

1 answer


I suppose you're talking about small wavelenght or large wavelength. In this case, the answer is that a wave with lower wavelenght has more energy than a wave with higher wavelenght.

You have to consider that the energy associated to an electromagnetic wave is, according to de Broglie:

E = hf

where h is the Planck constant (which is, more or less, h = 6.626·10-34 Js) and f is the frequency of the wave. The relationship between frequency and wavelenght is given by

f = c/lambda

where c is the speed of light and lambda the wavelenght. So finally you have

E = hc/lambda

According to this equation, the higher the wavelenght, the lower the energy.

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Coulomb's Law states that the magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each charge and inversely proportional to the square of the distance between the charges. A link is provided to the Wikipedia article.

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To calculate the number of photons, you can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of light in meters. After finding the energy per photon, you can divide the given energy threshold by this value to determine how many photons are needed.

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if you look down on pistol you should note a date over the chamber area. that is when it was made......................

OP:

If that is the case, then my pistol was made in 1601; around 300 years before the patent was awarded.

Then there is the 'f' at the end of that, which might denote June, it being the sixth month of the year.

I really don't think that is the answer, but thanks for your time.

The date of manf. for (most) lugers is directly over the chamber. Some exceptions as with letters 'byf' or letter 'G' or 'K'. I would greatly appreciate SEEING a 1601 over the chamber area of a luger . A luger COULD have the serial # 1601f, but that would be on the side or bottom of barrel. Are your sure it's a luger ????? A picture will tell.

OP:

The number and letter series is on the bottom of the barrel, under a crown with an "N" over it. I have checked over and over again and I cannot see anything marked over the chamber.

Yes, I am sure that it is a luger. I'll get a picture up when I can find time.

OP:

Did some more research and found out that I have a civilian luger. It has GERMANY stamped on the side IAW the import laws the U.S. had back in the early half of the 20th century. No book or person I have talked to can still point me in the right direction for it's date of manufacter, however Lugers like mine were made and imported in large quantities circa 1930 to help Germany pay off their World War 1 debt. Everything I have found concerning Lugers in any detail are concerned with the 9mm models, mine being a 7.65mm.

Also the marking below the 1601 is not an "f", but rather a "p" in the old German script.

I guess it is the best I can get right now.

Thanks for all your help internet.

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