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KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). The molar mass of KHP is approximately 204.22 g/mol. 1.54g of KHP is equivalent to 0.00754 mol of KHP. 1 mole of NaOH reacts per mole of KHP, so .00754 mol of NaOH are needed.
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Since KHP is an unknown (name for a) chemical compound the molarity can not be calculated by lack of data.The molar mass (m) of KHP ANDthe number (n) of H+ per mol KHP (maybe 1 when monoprotic?) is necessary for calculation, according to this formula:(M*V)NaOH = (n*mass/m)KHPso:[OH-] (mol.L-1) * 0.02850 (L NaOH sol'n) = n (mol H+.mol-1 KHP) * 0.7154 (g KHP) / m (g.mol-1 KHP)
To standardize 1N H2SO4 with KHP, you would first prepare a solution of KHP of known concentration. Then, titrate the KHP solution with the 1N H2SO4 solution until the endpoint is reached. The volume of H2SO4 used in the titration can then be used to calculate the exact concentration of the H2SO4 solution.
The molar mass of potassium hydrogen phthalate (KHP) is approximately 204.23 g/mol. Therefore, in 1 gram of KHP, there is approximately 0.00489 moles (1/204.23).
molar mass of KHP is 204.2g/mole. the formula for KHP is C8H5O4K therefore, (12.01*8)+(1.008*5)+(16*4)+39.1 = 204.2g/mol
The molar mass of potassium hydrogen phthalate (KHP) is approximately 204.22 g/mol.
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.