A 10' pole stands 10' to the left of a 100' pole on a level plane At what height on the 100' pole could it be bent over touching the 10' pole and the ground?
44.5' Using Pythagoras' theorem a^2 = b^2 +c^2 and the fact that
the pole is 100' in length, we can make two simultaneous equ's: a^2
= b^2 + (10)^2 and a + b = 100 /| a / |b /___ | 10