Let us use v2 = u2 + 2 a S
v = 0, S = 0.27 m and a = g = -9.8 m/s2
Plugging and solving for u we get, u = 2.3 m/s
Hence take-off velocity is 2.3 m/s
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ā 11y agoTo determine the take-off velocity of a jump of 0.27 m, you would need to know additional information, such as the angle at which the jump is launched, acceleration due to gravity, and the height of the jump. These variables are necessary to calculate the initial velocity required to achieve a jump height of 0.27 m.
Velocity squared is calculated by multiplying the velocity of an object by itself. For example, if the velocity of an object is 10 m/s, then the velocity squared would be 10 m/s * 10 m/s = 100 m/s^2.
To find the uniform velocity, divide the distance traveled by the time taken. Velocity = Distance / Time Velocity = 602 m / 250 s Velocity = 2.408 m/s Therefore, the uniform velocity of the object moving 602 m East in 250 seconds is 2.408 m/s.
The final velocity can be calculated using the formula: final velocity = initial velocity + acceleration Ć time. Given: initial velocity = 24 m/s, acceleration = 2 m/sĀ², and time = 8 seconds. Plugging in the values: final velocity = 24 m/s + 2 m/sĀ² Ć 8 s = 24 m/s + 16 m/s = 40 m/s. Therefore, the final velocity of the car is 40 m/s.
The change in velocity is the final velocity minus the initial velocity. For example, if the initial velocity is 10 m/s and the final velocity is 20 m/s, the change in velocity is 10 m/s.
The momentum of the car is 300 kg m/s. We can find the velocity by dividing the momentum by the mass of the car: velocity = momentum / mass. Therefore, velocity = 300 kg m/s / 2000 kg = 0.15 m/s.
3042 m
m=0.45 Kgchange in velocity= Vf - Vi =7-(-4)=11m/s.Rate of change of velocity = (11/0.04) m/s2Average force on ball = m x (11/0.04) = 123.75 newton Answer
Velocity squared is calculated by multiplying the velocity of an object by itself. For example, if the velocity of an object is 10 m/s, then the velocity squared would be 10 m/s * 10 m/s = 100 m/s^2.
given that: weight(F)=555N final velocity(v)=1.9m/s initial velocity(u)=0 change in momentum=? we have F=mg 555=m x g 55.5kg=m change in momentum=m(v-u) =55.5 X1.9 =105.45kg m/s
Initial velocity is the velocity an object begins with Final velocity is the velocity at which the object ends up in Say a car is travelling at 13 m/s and then crashes into a wall stopping it it's intitial velocity was 13 m/s and it's final velocity is at 0 m/s or Say a car starts off at 5 m/s but then accelerates from 5 m/s to 10 m/s. It's inital velocity would be 5 m/s but it's resulting or final velocity is 10 m/s
To find the uniform velocity, divide the distance traveled by the time taken. Velocity = Distance / Time Velocity = 602 m / 250 s Velocity = 2.408 m/s Therefore, the uniform velocity of the object moving 602 m East in 250 seconds is 2.408 m/s.
velocity is expressed in m/s
Velocity=m m=rise/run
The change in velocity is the final velocity minus the initial velocity. For example, if the initial velocity is 10 m/s and the final velocity is 20 m/s, the change in velocity is 10 m/s.
The final velocity can be calculated using the formula: final velocity = initial velocity + acceleration Ć time. Given: initial velocity = 24 m/s, acceleration = 2 m/sĀ², and time = 8 seconds. Plugging in the values: final velocity = 24 m/s + 2 m/sĀ² Ć 8 s = 24 m/s + 16 m/s = 40 m/s. Therefore, the final velocity of the car is 40 m/s.
The momentum of the car is 300 kg m/s. We can find the velocity by dividing the momentum by the mass of the car: velocity = momentum / mass. Therefore, velocity = 300 kg m/s / 2000 kg = 0.15 m/s.
The final velocity of the car can be calculated using the formula: final velocity = initial velocity + (acceleration x time). Plugging in the values, the final velocity is 24 m/s + (2 m/s^2 x 8 s) = 24 m/s + 16 m/s = 40 m/s. Hence, the final velocity of the car is 40 m/s.