Yes, S3 is commonly associated with fluid overload, as it can indicate impaired ventricular filling from increased blood volume. It is often heard in conditions like heart failure, where there is an excess of fluid in the circulatory system.
The dimension of voltage is energy per charge, represented in units of volts (V).
The volume of a standard hexagon can be given by the product of 6 times the length of one side of the hexagon and the height. Note that for a hexagon to have volume, it must have another dimension that is height.
char *strmerge (char *s3, const char *s1, const char *s2) { strcpy (s3, s1); strcat (s3, s2); return s3; }
let s1,s2,s3 be three sides of a triangle.import java.lang.*;import java.io.*;import java.util.*;class Triangle{public static void main(String args[]){boolean test=false;int s1,s2,s3;Scanner input = new Scanner(System.in);System.out.println("enter the side1 of triangle");s1=input.nextInt();System.out.println("enter the side2 of triangle");s2=input.nextInt();System.out.println("enter the side3 of triangle");s3=input.nextInt();if((s1*s1)==(s2*s2)+(s3*s3)){test=true;}else if((s2*s2)==(s1*s1)+(s3*s3)){test=true;}else if((s3*s3)==(s1*s1)+(s2*s2)){test=true;}if(test==true)System.out.println("Entered sides form a right angle triangle.....");elseSystem.out.println("Entered sides dosn't form a right angle triangle.....");}}
S1+s2+s3
s1 = 21 in s2 = 2s3 - 3 in s2 + s3 > s1 2s3 - 3 + s3 > 21 3s3 - 3 > 21 3s3 > 24 s3 > 8 s2 - s3 < s1 2s3 - 3 - s3 < 21 s3 - 3 < 21 s3 < 24 So that, 8 < s3 < 24, and 2(8) - 3 < s2 < 2(24) - 3 13 < s2 < 45
* Pt = s1 + s2 + s3
bh + (S1+ S2 + S3)H
TOC is Tactical Operations Center. Think S1-S3.
Hold S3 button about 3 seconds, then press S3 agaoin once. Tuesday and seconds digit will flash. Push S1 button and seconds will reset to zero. Push S2 button to change modes, then S1 button to advance. When finished, press S3 once more. Note: Buttons on watch are S2, S1, S3. IN THAT ORDER, if watch face is facing you.
bh+(S1+S2+S3)h
bh(s1+s2+s3)h
Answer: Surface area = bh/2 + (S1+ S2 + S3)Hin general surface area of a prism is2 × area of base + perimeter of base × HSo in particular, for the triangular prism, we have the answer above. Here is why.So h is the height of the triangular base and 1/2(bh) is the area of that triangle. 2x that isbh so that is where the bh part of the formula comes from.Now s1, s2 and s3 are the sides. So (s1+s2+s3) is the perimeter of the base. Let H be the height of the prism, then we have (s1+s2+s3)H in the second part of the formula.
char* strcat (char* destination, const char* source) { char* return_value = destination; // temp destination for return while (*(destination++) != '\0'); // find end of initial destination while ((*(destination++) = *(source++)) != '\0'); // copy source to end of destination return return_value; // return original value of destination }