Twice the energy means twice the frequency, and therefore half the wavelength.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
An atom can absorb a photon of 5000 wavelength through the process of photon absorption, where the energy of the photon is transferred to the atom, promoting an electron to a higher energy state within the atom. The size of the atom, in this case 1 angstrom, does not limit its ability to absorb the photon, as the interaction is determined by the energy of the photon and the energy levels of the atom.
The energy of a photon is given by E = hc/λ, where h is the Planck constant, c is the speed of light, and λ is the wavelength. Plugging in the values gives E = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (600 x 10^-9 m) = 3.31 x 10^-19 J.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The frequency of a photon with a wavelength of 6000 Ångströms can be calculated using the formula: frequency = speed of light / wavelength. For this case, the speed of light is approximately 3.00 x 10^8 m/s. Converting the wavelength to meters, we get 6.00 x 10^-7 m. Plugging these values into the formula, we find the frequency to be approximately 5.00 x 10^14 Hz.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
An atom can absorb a photon of 5000 wavelength through the process of photon absorption, where the energy of the photon is transferred to the atom, promoting an electron to a higher energy state within the atom. The size of the atom, in this case 1 angstrom, does not limit its ability to absorb the photon, as the interaction is determined by the energy of the photon and the energy levels of the atom.
First get the wavelength in meters by multiplying Plancks constant (in units of J-sec) times the speed of light (in m/sec) and divided by the energy. Then change to nanometers by multiplying by 1 billion.
38.4 *10-34J
The energy of a photon is given by E = hc/λ, where h is the Planck constant, c is the speed of light, and λ is the wavelength. Plugging in the values gives E = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (600 x 10^-9 m) = 3.31 x 10^-19 J.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The frequency of a photon with a wavelength of 6000 Ångströms can be calculated using the formula: frequency = speed of light / wavelength. For this case, the speed of light is approximately 3.00 x 10^8 m/s. Converting the wavelength to meters, we get 6.00 x 10^-7 m. Plugging these values into the formula, we find the frequency to be approximately 5.00 x 10^14 Hz.
The energy of a photon can be calculated using the equation E = hc/λ, where E is energy, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. Plugging in the values, we get E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / 400 x 10^-9 m = 4.97 x 10^-19 Joules.
A photon is a particle with negligible mass, whose energy and momentum are determined by its frequency and wavelength. It is a fundamental particle that carries electromagnetic radiation.
An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.
The energy of light is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. Plugging in the values, the energy of light with a wavelength of 4.06 x 10^-11 m is approximately 4.89 x 10^-15 J.
12.5 terahertz. If your wavelength is in meters.