What is the sun's gravitational field?

Answer 1

Everything is. There\'s no maximum distance past which the force of gravity

disappears. Its magnitude certainly decreases as the inverse square of the

distance, but it never becomes zero, and can be calculated at any distance.

There is a gravitational force between the smallest grain of sand on the beach on

the far side of the farthest planet in orbit around the farthest star on the far side

of the farthest galaxy from Earth, and the lint in your pocket.
The entire solar system, with its planets, dwarf planets, asteroids, comets, and assorted debris, is in the sun's gravitational field.

Answer 2

The sun's gravitational field is the force of gravity exerted by the sun on objects in its vicinity. This gravitational field is what keeps planets and other objects in orbit around the sun. The strength of the sun's gravitational field weakens with distance from the sun.

Answer 3

A gravitational field is a vector velocity field. Matter creates a velocity field v = (GM/r)^.5, the Gravitational potential energy is V = -mGM/r = -mv^2. The total Energy is W = -mGM/r + cmV = -vh/l + cP.

The gravitational field does not distort space ala Einstein, matter creates a velocity field.

Answer 4

The field is attractive in nature.

A mass experiences a force in a gravitational field.

The force obeys the inverse square law.

The field lines are radial from the massive point object whose field is concerned.

Answer 5

Yes..... Our Earth and the rest of the planets would fly away from the Sun if it had no gravitional force. But also the Sun would blow apart if it had no gravity! The Sun is a full-time Fusion nuclear bomb! If the Sun had no gravity then the force of the explosion would send the Sun's matter flying outward, but the gravitional pull keeps the explosion in place!

Answer 6

The answer is 274nkg^-1

Use the Equation GM/r^2

G is the gravitational constant = 6.67x10^-11

M is the mass of the sun 1.99x10^30

r the radius of the sun ( The distance from the centre to the outer.) = 6.96x10^8

Answer 7

The acceleration of gravity at the 'surface' of the sun (however that happens to be

defined) is 273.6 meters per second2. That's about 27.9 times the acceleration of

gravity on the earth's surface.

So, on their next field trip to the sun, each 72-pound kid in the 5th grade will weigh

a ton when they get there. Their 5th grade teacher, who already weighs a ton, will

weigh about 55,800 pounds up there, so they're saving her a whole row of seats

on the school bus for the field trip.

Answer 8

F = Gravitation Constant x Mass of Earth x Mass of Sun / Radius, or distance between Earth and the Sun, squared

F = ((6.67384 x 10^-11 m^3 kg^-1 s^-2) ((5.9736 x 10^24 kg) (1.9891 x 10^30 kg))) / (140000000000 meters)^2

F = 4.046 x 10^22 kg m/s^2

F = 4.046 x 10^22 Newtons

Answer 9

There are two answers to this question:

In order to know the gravitational pull of the Sun, you have to ask, "against what other body?"

The force of gravity between two objects is given by Newton's law as

F = G(Mm/r2)

where F is the force in newtons, G in the universal gravitational constant, 6.674 x 10-11 n m2 kg-2, M and m are the masses in kilograms of the two objects, and r is the distance in meters between them.

Plugging in M = 1.9891 x 1030 kg for the Sun, m = 5.9736 x 1024 kg for the Earth, and r = 1.49598 x 1011 m for the semi-major axis of the orbit of the Earth around the Sun, we get F = 3.543 x 1022 n as the force the the Sun exerts on the Earth and as the force the the Earth exerts on the Sun.

The second answer is that, if you could stand on the surface of the Sun (yeah, that's a big if), the gravity would be 274 m s2, or about 28 times that of Earth.

Answer 10

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This is what keeps Earth in place. If there was no gravitational feilds, the Earth would crash into other planets, and space objects. It pushes the moon away from the Earth and the sun pushes the Earth away. Like repelling magnets.

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