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What is the relation between k and permittivity of free space?

Anonymous

∙ 9y ago

Updated: 6/3/2024

The permittivity of free space, denoted by ε₀, is a physical constant that represents the ability of a material to store electrical energy in an electric field. It is related to the Coulomb's constant k (also known as electrostatic constant) by the equation k = 1 / (4πε₀), where k is a proportionality constant in Coulomb's law.

AnswerBot

∙ 9mo ago

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Continue Learning about Physics

What is the relationship between the electric field intensity (E), charge density (q), and permittivity of free space ()?

The relationship between the electric field intensity (E), charge density (q), and permittivity of free space () is given by the equation E q / (). This equation shows that the electric field intensity is directly proportional to the charge density and inversely proportional to the permittivity of free space.

What is the relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system?

The relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system is described by Gauss's Law, which states that the electric field (E) at a point in space is directly proportional to the electric charge density () at that point and inversely proportional to the permittivity of free space (). Mathematically, this relationship is represented as E / .

What is epsilon naut?

Epsilon naught (ε₀) is the vacuum permittivity constant, representing the electric permittivity of free space. It has a value of approximately 8.85 x 10^(-12) farads per meter.

Units for permittivity of free space?

The unit for permittivity of free space is farads per meter (F/m). It is denoted by the symbol ε0 and represents the ability of a vacuum to permit the transmission of electric field lines.

What is the capacitance between two concentric spheres?

The capacitance between two concentric spheres is determined by the radius of the spheres and the permittivity of the material between them. It can be calculated using the formula C 4rr / (r - r), where C is the capacitance, is the permittivity of free space, r is the radius of the inner sphere, and r is the radius of the outer sphere.

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Related Questions

What is the relationship between the electric field intensity (E), charge density (q), and permittivity of free space ()?

The relationship between the electric field intensity (E), charge density (q), and permittivity of free space () is given by the equation E q / (). This equation shows that the electric field intensity is directly proportional to the charge density and inversely proportional to the permittivity of free space.

What is the relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system?

The relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system is described by Gauss's Law, which states that the electric field (E) at a point in space is directly proportional to the electric charge density () at that point and inversely proportional to the permittivity of free space (). Mathematically, this relationship is represented as E / .

What is epsilon naut?

Epsilon naught (ε₀) is the vacuum permittivity constant, representing the electric permittivity of free space. It has a value of approximately 8.85 x 10^(-12) farads per meter.

Units for permittivity of free space?

The unit for permittivity of free space is farads per meter (F/m). It is denoted by the symbol ε0 and represents the ability of a vacuum to permit the transmission of electric field lines.

What is the capacitance between two concentric spheres?

The capacitance between two concentric spheres is determined by the radius of the spheres and the permittivity of the material between them. It can be calculated using the formula C 4rr / (r - r), where C is the capacitance, is the permittivity of free space, r is the radius of the inner sphere, and r is the radius of the outer sphere.

What is Relative dielectric constant for vacuum?

YES IT IS. Any quantity which is ratio of two physical quantities having same unit is dimensionless. Dielectric constant is ratio of Permittivty of medium to the permittivity of free space. As Permittivity of medium and permittivity of free space both have same units(F/m ie Farad/meter) dielectric constant becomes dimensionless quantity

What is the formula for calculating the electric flux through a surface due to a point charge, taking into account the permittivity of free space, represented by the symbol epsilon naught?

The formula for calculating the electric flux through a surface due to a point charge is given by q / , where is the electric flux, q is the charge, and is the permittivity of free space.

What is the conductivity of free space?

The conductivity of free space, also known as vacuum permittivity, is approximately (8.854 \times 10^{-12} , \text{F/m}). It represents the ability of free space to transmit electric fields.

What is the significance of Coulomb's constant, also known as the electric constant or permittivity of free space (), in the context of electrostatic interactions?

Coulomb's constant, also known as the electric constant or permittivity of free space (), is significant in electrostatic interactions because it determines the strength of the force between charged particles. It is a fundamental constant in physics that quantifies the strength of the electrostatic force between charged objects in a vacuum. The value of Coulomb's constant influences the magnitude of the force between charged particles and plays a crucial role in understanding and predicting electrostatic interactions.

What is dimension of permittivity of vacumm?

The dimension of permittivity of vacuum, also known as vacuum permittivity or electric constant, is F/m (coulomb per volt per meter). It is denoted by ε₀ and has a value of approximately 8.854 x 10^-12 F/m.

Velocity of travelling wave throgh a cable of relative permittivity 9 is?

The velocity of a wave traveling through a cable is given by the formula ( v = \frac{1}{\sqrt{\mu \epsilon}} ), where ( \mu ) is the permeability of the medium and ( \epsilon ) is the permittivity of the medium. Given that the relative permittivity ( \epsilon_r = 9 ), the permittivity of the medium ( \epsilon ) can be calculated by ( \epsilon = \epsilon_0 \times \epsilon_r ), where ( \epsilon_0 ) is the permittivity of free space. By substituting the values of ( \mu ) and ( \epsilon ) into the formula, the velocity of the wave through the cable can be determined.

What is the capacitance of a twin copper wire?

The capacitance of a twin copper wire would depend on various factors such as the distance between the wires, the diameter of the wires, and the dielectric material between them. It can be calculated using the formula C = (ε0 * εr * A) / d, where C is the capacitance, ε0 is the permittivity of free space, εr is the relative permittivity of the material between the wires, A is the area of each wire, and d is the distance between the wires.

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