An alpha particle is a helium-4 nucleus. Look up the number of the element, and subtract two from that (since helium has 2 protons). As for the number, subtract 210 - 4 (since the alpha particle has an Atomic Mass of 4).
In alpha decay, the parent element releases an alpha particle, which is a helium nucleus consisting of 2 protons and 2 neutrons. The daughter element formed has an atomic number 2 less and a mass number 4 less than the parent element. In beta decay, the parent element undergoes a transformation where a neutron is converted into a proton, emitting an electron (beta particle) and an antineutrino. The daughter element formed has an atomic number 1 more than the parent element.
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The element formed during alpha decay is a new element with an atomic number that is 2 less and an atomic mass that is 4 less than the original element. An alpha particle, which consists of 2 protons and 2 neutrons, is emitted during the process.
No, the daughter element after alpha decay has less atomic number than the parent (reducing charge), but the total charge (protons) in the nucleus remains the same. The daughter element gains stability by emitting an alpha particle, which consists of two protons and two neutrons.
Nuclear decay, specifically beta decay or alpha decay, can result in the formation of a different element. In beta decay, a neutron decays into a proton, resulting in the formation of a different element with the same mass number but a different atomic number. In alpha decay, an alpha particle (helium nucleus) is emitted, leading to the formation of a different element with a lower atomic number.
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
In alpha decay, the parent element releases an alpha particle, which is a helium nucleus consisting of 2 protons and 2 neutrons. The daughter element formed has an atomic number 2 less and a mass number 4 less than the parent element. In beta decay, the parent element undergoes a transformation where a neutron is converted into a proton, emitting an electron (beta particle) and an antineutrino. The daughter element formed has an atomic number 1 more than the parent element.
The first radioactive element formed when uranium-238 decays is thorium-234. Uranium-238 undergoes alpha decay to form thorium-234.
When astatine-218 undergoes alpha decay, it emits a helium nucleus (alpha particle) and transforms into the new element, polonium-214. This process reduces the atomic number of the nucleus by 2 and the mass number by 4.
When Fr-223 undergoes alpha decay, it emits an alpha particle consisting of two protons and two neutrons. This transforms the nucleus into a different element with atomic number decreased by 2 and atomic mass number decreased by 4.
That depends on the type of decay, alpha and beta decay change the atom into a different element but gamma decay does not.
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The element formed during alpha decay is a new element with an atomic number that is 2 less and an atomic mass that is 4 less than the original element. An alpha particle, which consists of 2 protons and 2 neutrons, is emitted during the process.
Alpha decay is a kind of radioactive decay in which an alpha particle is emitted from an atom. An alpha particle consists of two protons and two neutrons. Therefore, when an atom of an element undergoes alpha decay, it loses two protons, which changes the atom from one element to another. This is because each different element is identified by the number of protons in its atomic nuclei.
Alpha decay is a kind of radioactive decay in which an alpha particle is emitted from an atom. An alpha particle consists of two protons and two neutrons. Therefore, when an atom of an element undergoes alpha decay, it loses two protons, which changes the atom from one element to another. This is because each different element is identified by the number of protons in its atomic nuclei.
After the nucleus of a radioactive element undergoes changes, it can transform into a different element or isotope through processes like alpha or beta decay. This transformation occurs as the nucleus tries to achieve a more stable configuration.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.