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What is the mass of the car if the net force on the car is 3000 N east?
Wiki User
∙ 6y ago
To determine the mass of the car, we would need to know the acceleration of the car. Using Newton's second law (F = ma), we can rearrange the equation to find mass (m = F/a) if we know the acceleration. Without the acceleration value, we cannot calculate the mass of the car based solely on the net force.
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What will the stopping distance be for 3000-kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, you need to know the deceleration of the car. Here, deceleration can be calculated using Newton's second law: deceleration = force / mass. With the given force of -3000 N and mass of 3000 kg, the deceleration would be -1 m/s^2. Using the equation of motion, final velocity^2 = initial velocity^2 + 2 * acceleration * distance, you can calculate the stopping distance.
What net force is required to accelerate a car at a rate of 2 meters per second if the car has a mass of 3000 kilograms?
The net force required to accelerate the car at a rate of 2 meters per second squared with a mass of 3000 kilograms would be 6000 Newtons. This is calculated using Newton's second law, F = m*a, where F is the force, m is the mass, and a is the acceleration.
What net force is required to accelerate a car at a rate of 2 ms2 if the car has a mass of 3000kg?
The net force required to accelerate the car at a rate of 2 m/s^2 is 6000 N. This is calculated using Newton's second law, F = ma, where F is the force, m is the mass of the car (3000 kg), and a is the acceleration (2 m/s^2). So, F = 3000 kg * 2 m/s^2 = 6000 N.
What will the stopping distance be for a kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, we need to first find the deceleration of the car using the formula: force = mass x acceleration. Given that force = -3000 N and mass = kg, we can find the acceleration. Once the acceleration is known, we can use the equation of motion: final velocity^2 = initial velocity^2 + 2 x acceleration x distance to calculate the stopping distance.
What will the stopping distance be for a 3000-kg car if -3000 N of force are applied when the car is traveling 10 ms?
To calculate the stopping distance, we need to know the deceleration of the car, which can be determined using the equation force = mass x acceleration. In this case, the deceleration would be -1 m/s^2. Using the equation stopping distance = (initial velocity)^2 / (2 x acceleration), we find the stopping distance to be 50 meters.
With what force will a car hit a tree if the car has a mass of 3000 kg and it is accelerating at a rate of 2 ms?
Force = (mass in kg)x(acceleration in m.s^-2)
What net force is required to accelerate a car at a rate of 2 meters per second if the car has a mass of 3000 kilograms?
The net force required to accelerate the car at a rate of 2 meters per second squared with a mass of 3000 kilograms would be 6000 Newtons. This is calculated using Newton's second law, F = m*a, where F is the force, m is the mass, and a is the acceleration.
What will the stopping distance be for 3000-kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, you need to know the deceleration of the car. Here, deceleration can be calculated using Newton's second law: deceleration = force / mass. With the given force of -3000 N and mass of 3000 kg, the deceleration would be -1 m/s^2. Using the equation of motion, final velocity^2 = initial velocity^2 + 2 * acceleration * distance, you can calculate the stopping distance.
A car whose mass is 2000 kg is accelerated uniformly from rest to speed at 15ms in 10 seconds The net force accelerating the car is?
3000 N
A tow truck exerts a force of 3000 N on a car accelerating it at 2 meters per second what is the mass of the car?
The mass of an object can be determined by taking (the net force in Newtons) divided by (the acceleration in meters per second per second).
What net force is required to accelerate a car at a rate of 2 ms2 if the car has a mass of 3000kg?
The net force required to accelerate the car at a rate of 2 m/s^2 is 6000 N. This is calculated using Newton's second law, F = ma, where F is the force, m is the mass of the car (3000 kg), and a is the acceleration (2 m/s^2). So, F = 3000 kg * 2 m/s^2 = 6000 N.
If An automobile weighs 3000 pounds It is parked on a level driveway With what force is the driveway pushing up on the tires of the car?
3000 pounds of upward force is reacting to the downward force. Assuming 4 tires, and equal distribution of mass, that would be 750 pounds per tire. Engine location matters, as does other load distributions within the car. The total upward force remains exactly 3000 pounds. All of the force is due to gravitational attraction.
What will the stopping distance be for a kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, we need to first find the deceleration of the car using the formula: force = mass x acceleration. Given that force = -3000 N and mass = kg, we can find the acceleration. Once the acceleration is known, we can use the equation of motion: final velocity^2 = initial velocity^2 + 2 x acceleration x distance to calculate the stopping distance.
What will the stopping distance be for a 3000kg car if 3000 N of force are applied when the car is traveling 10 ms?
The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.
A person pushes a 3000 kg car and it accelerates 6mss what is the force applied?
Force = mass X acceleration, F=ma=3000kg X 6m/s2=18000kgm/s2=18 kilonewtons
Force mass multiplied by acceleration .....how much force is needed to accelerate a 1000-kg car at a rate of 3 meters per second squared?
The force needed can be calculated using the formula: Force = mass x acceleration. Plugging in the values, Force = 1000 kg x 3 m/s^2 = 3000 N. Therefore, 3000 Newtons of force is needed to accelerate a 1000-kg car at a rate of 3 meters per second squared.
Explain how a car with a large mass can have the same acceleration as a car with a small mass?
because the force the drives it
