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The magnitude of the torque about a pivot point is given by the product of the force applied and the distance from the pivot point to the line of action of the force, multiplied by the sine of the angle between the force and the lever arm. Mathematically, torque = force * distance * sin(angle).
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When a force makes an object tends to rotate?
When a force is applied to an object, causing it to rotate, this force creates a torque. Torque is the tendency of a force to rotate an object around an axis or pivot point. The magnitude of the torque depends on the force applied and the distance from the pivot point.
In the figure force F 2 acts half as far from the pivot asF 1 What magnitude of F 2 causes the net torque on the rod to be zero?
If force F1 is farther from the pivot than force F2, then F2 must be twice the magnitude of F1 to create a net torque of zero on the rod. This is because torque is the product of the force and the distance from the pivot point, so for the torques to balance out, the force nearer to the pivot must be greater.
Why torque is zero when force is applied to point that passes through pivot point?
When a force is applied at a point that passes through the pivot point, the lever arm (the perpendicular distance between the pivot point and the point of force application) is zero. Since torque is defined as force multiplied by the lever arm, when the lever arm is zero, the torque is also zero. This means that the force does not create a rotational motion around the pivot point.
The size of the turning effect of a force depends on?
The size of the turning effect of a force, or torque, depends on the magnitude of the force and the distance from the pivot point at which the force is applied. The longer the distance from the pivot point, known as the moment arm, the greater the turning effect produced by the force.
How does a lighter lift a heaver person on a seesaw?
A lighter person sitting closer to the pivot point of a seesaw exerts a smaller torque compared to a heavier person sitting farther from the pivot point. This difference in torque allows the heavier person to be lifted. The principle involved is torque, or the rotational force, in relation to the pivot point.
When a force makes an object tends to rotate?
When a force is applied to an object, causing it to rotate, this force creates a torque. Torque is the tendency of a force to rotate an object around an axis or pivot point. The magnitude of the torque depends on the force applied and the distance from the pivot point.
In the figure force F 2 acts half as far from the pivot asF 1 What magnitude of F 2 causes the net torque on the rod to be zero?
If force F1 is farther from the pivot than force F2, then F2 must be twice the magnitude of F1 to create a net torque of zero on the rod. This is because torque is the product of the force and the distance from the pivot point, so for the torques to balance out, the force nearer to the pivot must be greater.
Why torque is zero when force is applied to point that passes through pivot point?
When a force is applied at a point that passes through the pivot point, the lever arm (the perpendicular distance between the pivot point and the point of force application) is zero. Since torque is defined as force multiplied by the lever arm, when the lever arm is zero, the torque is also zero. This means that the force does not create a rotational motion around the pivot point.
Does the center of mass have torque if it isn't a pivot point?
yes
The size of the turning effect of a force depends on?
The size of the turning effect of a force, or torque, depends on the magnitude of the force and the distance from the pivot point at which the force is applied. The longer the distance from the pivot point, known as the moment arm, the greater the turning effect produced by the force.
How does a lighter lift a heaver person on a seesaw?
A lighter person sitting closer to the pivot point of a seesaw exerts a smaller torque compared to a heavier person sitting farther from the pivot point. This difference in torque allows the heavier person to be lifted. The principle involved is torque, or the rotational force, in relation to the pivot point.
What is the magnitude of the torque about the point where the beam is bolted into place?
The magnitude of the torque depends on the force applied to the beam and the distance from the point where the beam is bolted. The torque can be calculated using the formula Torque = Force x Distance.
What are the 3 ways you can change torque?
You can change torque by adjusting the force applied, changing the distance between the force and the pivot point, or altering the angle at which the force is applied relative to the pivot point.
When measuring torque is a two foot-pound measurement the equivalent of two pounds of force applied one foot from the pivot point or one pound of force two feet from the pivot point?
The way torque works, these two cases give the same torque, or twisting force, to the object at the pivot point. To find the torque applied, multiply the force by the distance. Obviously this is the same in the two cases you describe.
What is meant by the lever arm of torque?
The lever arm of torque is the perpendicular distance between the pivot point of the object and the line of action of the force applied to it. It determines the effectiveness of the force in rotating an object around its pivot point. A longer lever arm results in greater torque.
Find the torque tau about the pivot due to the weight w of Gilles on the seesaw?
The torque due to Gilles' weight on the seesaw is equal to the weight of Gilles multiplied by the distance from the pivot point to where Gilles is sitting. This torque is given by the equation: torque = weight * distance.
A pendulum consists of an object of mass 1.21kg tht hangs at the end of a massless bar a distance 1.28m from the pivot point calculate the magnitude of the torque due to gravity about the pivot point?
The torque is the component of the weight that is perpendicular to the bar. So when the bar hangs vertically down, parallel to the force of gravity, there is no torque. If the bar makes an angle "A" with the vertical then the component of weight perpendicular to the bar would be mgSin(A) and the torque would be mgLSin(A) , where m= 1.21 kg, and L = 1.28m, g=9.8m/ss , so all you need is the angle "A".
