To calculate the energy of a photon, you can use the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J-s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting 760 nm to meters (760 x 10^-9 m) and plugging into the formula, the energy of a photon with a wavelength of 760 nm is approximately 2.61 x 10^-19 Joules.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
To determine the energy of a photon of orange light with a wavelength of 600 nm, we can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting the wavelength to meters (600 nm = 600 x 10^-9 m), we can plug the values into the formula to find the energy of the photon. The energy of a photon of orange light with a wavelength of 600 nm is approximately 3.31 x 10^-19 joules.
The wavelength can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging the given energy value into the equation and solving for λ gives a wavelength of approximately 608 nm.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
610 nm
The energy of this photon is 3,7351.10e-19 joules.
To determine the energy of a photon of orange light with a wavelength of 600 nm, we can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting the wavelength to meters (600 nm = 600 x 10^-9 m), we can plug the values into the formula to find the energy of the photon. The energy of a photon of orange light with a wavelength of 600 nm is approximately 3.31 x 10^-19 joules.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
4.9695 nm
The wavelength can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging the given energy value into the equation and solving for λ gives a wavelength of approximately 608 nm.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.
3.84 x 10-19 joules.