The efficiency of the pulley system is calculated as the ratio of output work to input work. In this case, the output work is the work done in lifting the engine (2000 N * 3 m), which is 6000 joules. The input work is the work done by the operator (250 N * 3 m), which is 750 joules. Therefore, the efficiency is 6000/750 = 8 or 800%.
The mechanical advantage of 4 means the operator only needs to apply a quarter of the force needed to lift the engine. Therefore, the operator will only need to apply 500 newtons of force to lift the 2000 newton engine.
To find the weight of the engine (w), we can use the formula: work done = force × distance. In this case, the work done lifting the engine is the same whether the distance is lifted in one go or 30 small steps. Therefore, 250N × 3m = 30 steps × w × 3m. Solving for w gives w = 250 N.
The ratio of output work to input work expressed as a percentage is called the efficiency of the engine. It measures how well an engine converts fuel energy into useful work output. A higher efficiency indicates that the engine is more effective at converting energy into work.
100% efficiency is impossible for a heat engine working between two reservoirs at different temperatures according to the second law of thermodynamics.
The efficiency of the engine is calculated using the formula: Efficiency = (Useful work output / Total heat input). In this case, the useful work output is the heat input minus the waste heat, which is 500,000 J. Therefore, the efficiency of the engine would be (500,000 / 2,000,000) * 100% = 25%.
The mechanical advantage of 4 means the operator only needs to apply a quarter of the force needed to lift the engine. Therefore, the operator will only need to apply 500 newtons of force to lift the 2000 newton engine.
What is the value of Wi? 7,500 joules
400
You will need 8 drops of chain. So the operator must apply 250 newtons to the 8th drop. The other 7 drops of chain must be reeved through the pulley system.
wi 7500 joules fi 250 newtons di 30 meters A+
Gasoline engines have a 30% efficiency, as compared to a Diesel engine having 40% efficiency. COOL HUH
The maximum Thermal Efficiency of Petrol Engine or Gasoline Engine or Otto Cycle Engine is about 25-30%.
It is not a good efficiency engine.
Slip=100%-Efficiency Efficiency=Observed Speed or Distance / Engine Speed or Distance Mean Apparent Slip = Distance Run by Propeller - Distance Run by Ship / Distance Run by Propeller Distance Run by Propeller = Picth X Total Engine Revolutions per day / 1852 I wish this can help those who are in need of this formula. Rgds Ahmad email: ths_n_tht@Yahoo.com
It is not a good efficiency engine.
10Kg X 9.81 m/s^2 = 98.1 newtons 98.1N X 4m = 392.4 joules 392.4J/500J X 100% = 78.48% efficient
no