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What is the efficiency of a car's engine when he input is 20000 joules and the waste heat is 15000 joules?
Wiki User
∙ 9y ago
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
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What is the change in the internal energy of a system that does 5000 joules of work and absorbs 20000 joules of heat?
1,000 J
What the internal energy of a system that does 5000 joules of work and absorbs 20000 joules of heat?
The internal energy change of the system would be the sum of the heat absorbed and the work done on the system. Therefore, the internal energy change would be 20000 J (heat absorbed) + 5000 J (work done) = 25000 J.
A machine has an efficiency of 70 percent how much work does the machine do when 20000 J of work is done on it?
If the machine has an efficiency of 70%, it means that it only converts 70% of the input energy into useful work. Therefore, the work done by the machine would be 70% of the 20000 J of work done on it, which is 0.7 * 20000 J = 14000 J.
An American satellite with a mass of 20000 kg is 40 meters from an enemy satellite with a mass of 15000 kg What is the gravitational force between them?
The gravitational force between the two satellites can be calculated using Newton's law of universal gravitation: F = G * (m1 * m2) / r^2, where G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), m1 and m2 are the masses of the two satellites, and r is the distance between them. Plugging in the values, we get F = (6.674 x 10^-11) * (20000) * (15000) / (40)^2 = 0.314 N.
What is the minimum time needed to lift a 2000-N weight 10 meters using a motor with a maximum power rating of 8000 watts?
The minimum time needed to lift the weight can be found using the formula: time = work done / power The work done is given by the product of force and distance, so work = force * distance. Substitute the values into the formula and solve for time to find the minimum time needed.
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.75
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33.3% increase.
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What is the change in the internal energy of a system that does 5000 joules of work and absorbs 20000 joules of heat?
1,000 J
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