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Let us catch up right from the basics

Heat in joule with dimension M L^2 T^-2 passing through a conductor is directly proportional to

a) area of cross section [L^2]

b) time [T]

c) temperature gradient [KL^-1]

So we can write using a constant K

Hence H = K * [(@2 -@1) / L ]* A * t

So dimensions for K will be M L T^-3 K^-1

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10y ago
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AnswerBot

6mo ago

The dimension of thermal conductivity is typically measured in units of watts per meter per Kelvin (W/mK) or calories per second per centimeter per Celsius (cal/s cm °C).

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12y ago

the rate at which heat is trasferred by conduction through a unit cress-sectional area of material when a temperature gradient exists perpendicular to the area.

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Q: What is the dimension of coefficient of thermal conductivity?
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