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The de Broglie wavelength is a concept in quantum mechanics that describes the wave nature of a particle. It represents the wavelength associated with a particle's momentum, showing that particles such as electrons have both wave and particle-like properties. The de Broglie wavelength is inversely proportional to the momentum of the particle.

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Q: What is meant by the de broglie wavelength of a particle?
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De broglie derived a mathematical relationship between the mass and velocity of a moving particle and?

the wavelength of its associated wave, known as the de Broglie wavelength. This relationship is expressed by the de Broglie equation: λ = h / p, where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.


Why cannot a single wave represent a particle?

A single wave cannot represent a particle because waves and particles have different properties that cannot be fully described by the same model. While particles have a definite location and momentum, waves exhibit properties like interference and diffraction which are not compatible with the concept of a localized particle. This led to the development of wave-particle duality in quantum mechanics where particles exhibit both particle-like and wave-like behaviors.


In what field is De Broglie wavelength being measured?

The De Broglie wavelength is commonly used in the field of quantum mechanics to describe the wave-like behavior of particles, such as electrons or atoms. It provides insight into the wave-particle duality of matter, where particles can exhibit both wave-like and particle-like properties.


How do you find wavelength of an alpha particle when given the velocity?

The wavelength of an alpha particle can be found using the de Broglie wavelength equation: λ = h / p, where λ is the wavelength, h is Planck's constant (6.63 x 10^-34 m^2 kg / s), and p is the momentum of the particle, which is equal to the product of the mass of the alpha particle and its velocity.


If proton and an electron have the same speed which has the longer de Broglie wavelength?

The de Broglie wavelength is inversely proportional to the mass of the particle. Since a proton is much more massive than an electron, it will have a shorter de Broglie wavelength at the same speed.


What is de-Broglie wavelength of an atom at absolute temperature T K?

The de Broglie wavelength of an atom at absolute temperature T K can be calculated using the formula λ = h / (mv), where h is Planck's constant, m is the mass of the atom, and v is the velocity of the atom. At higher temperatures, the velocity of atoms increases, leading to a shorter de Broglie wavelength.


Does a photon have a de Broglie wavelength?

Yes, a photon does have a de Broglie wavelength, which is given by λ = h/p, where h is Planck's constant and p is the photon's momentum. Photons exhibit both wave-like and particle-like properties.


What did De Broglie refer to wavelike particle behavior as?

De Broglie referred to wavelike particle behavior as wave-particle duality.


What is the de Broglie wavelength in meters of a mosquito weighing 1.60 and flying at 1.42?

The de Broglie Wavelength of a mosquito can be calculated using a specific formula. For this example, the wavelength is 2.8 to the 28th power meters.


What is De broglie's theory?

De Broglie's theory, proposed by physicist Louis de Broglie in 1924, states that particles, such as electrons, can exhibit both wave-like and particle-like properties. It suggests that all matter, including particles like electrons, can have wave characteristics with a wavelength inversely proportional to its momentum. This concept is known as wave-particle duality.


What year was De Broglie's wavelength model created?

1924


Does the de broglie wavelength of a photon become longer or shorter as its velocity increases?

The de Broglie wavelength of a photon remains constant as its velocity increases because a photon always travels at the speed of light in a vacuum. The wavelength of light is determined by its frequency according to the equation λ = c / f.