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In the tan B position, the direction of the magnet depends on the specific orientation of the magnet. The north pole of the magnet points towards the geographical North Pole, while the south pole points towards the geographical South Pole. The direction can also be determined by using a compass, as the needle aligns with the magnetic field lines.
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What is Tanb position in Deflection magnetometer?
In a deflection magnetometer, the Tan B position is the location where the magnetic needle aligns itself tangentially to the Earth's magnetic field when no external magnetic field is present. It is an important reference point for determining the strength and direction of an external magnetic field.
What does the direction of arrow b indicate?
The direction of arrow b typically indicates movement or flow in a certain direction. This could refer to a vector quantity or a force acting on an object, pointing from the initial position to the final position of the object.
Choose the best description of a magnetic field line A Magnetic field lines for a bar magnet are parallel to the magnet B A magnetic field line shows the direction a compass needle would?
B. A magnetic field line shows the direction a compass needle would align in a magnetic field.
What kind of movement is the arm engaged in when going from position A to position B?
The arm is engaged in a motion called flexion when moving from position A to position B. This involves reducing the angle between the bones of the arm at a joint, such as the elbow or shoulder.
When you apply force at an angle to the direction of movement of the force does work. a. all c. some b. none d. a and b?
d. a and b.
What is tan20tan32 plus tan32tan38 plus tan38tan20?
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
What is Tanb position in Deflection magnetometer?
In a deflection magnetometer, the Tan B position is the location where the magnetic needle aligns itself tangentially to the Earth's magnetic field when no external magnetic field is present. It is an important reference point for determining the strength and direction of an external magnetic field.
What does the direction of arrow b indicate?
The direction of arrow b typically indicates movement or flow in a certain direction. This could refer to a vector quantity or a force acting on an object, pointing from the initial position to the final position of the object.
Choose the best description of a magnetic field line A Magnetic field lines for a bar magnet are parallel to the magnet B A magnetic field line shows the direction a compass needle would?
B. A magnetic field line shows the direction a compass needle would align in a magnetic field.
How do you find tan B if tan A equals 678?
tan A says nothing about tan B without further information.
How to find the direction of vector A by its x and y components?
Consider any two points on the vector, P = (a, b) and Q = (c, d). And lext x be the angle made by the vector with the positive direction of the x-axis. Then either a = c, so that the vector is vertical and its direction is straight up or a - c is non-zero. In that case, tan(x) = (b - d)/(a - c) or x = tan-1[(b - d)/(a - c)]
Why magnetism at the centre of a bar magnet is zero?
F = mB - mB =0 a bar magnet is placed in a uniform magnetic field B, its poles +m and -m experience force mB and mB along and opposite to the direction of magnetic field B.
The function cot 115 degrees is equivalent to A -tan 65 degrees B -tan 25 degrees C tan 25 degrees D tan 65 degrees?
B: -tan(25)
Diploma First Year Maths Important Questions List?
tan a=1/2 tan b=1/3 find tan (a-b)
What is the exact trigonometric function value of cot 15 degrees?
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
How do you find the poles of a magnet?
If there is a repulsion between A and N then A is North pole and B is South pole of the horse shoe magnet. If B and N repel each other the B is north and A is south of the horse shoe magnet.
