At STP1mol O2 = 22.4L1mol O2 = 6.022 x 1023 molecules O222.4L O2 = 6.022 x 1023 molecules O2Convert liters O2 to moles O23.36L O2 X (6.022 x 1023 molecules O2/22.4L O2) = 9.03 x 1022 molecules O2
We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.
To determine the limiting reactant, we need to compare the moles of Mg and O2 and see which is present in the lower amount. Then, using the stoichiometry of the balanced chemical equation for the reaction between Mg and O2, we can calculate the theoretical yield of MgO. From there, you can determine which reactant is limiting and calculate the theoretical yield based on that.
If the reaction is just between O2 and Al, the balanced equation would be:3O2 + 4Al -> 2Al2O3By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a periodic table to find atomic masses) So we get:26.98*2+16*3= 102.0One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
An exothermic reaction is a type of reaction where a large amount of energy is released in the form of heat. This occurs when the energy of the products is lower than the energy of the reactants, leading to a net release of energy. Examples include combustion reactions and reactions involving the formation of more stable bonds.
keq=[SO3]2[O2] [So3]2
No, the chemical equation is not balanced. The correct balanced equation is 2SO2 + O2 → 2SO3.
adding SO2
Yes, the reaction 2SO2 + O2 -> 2SO3 is a combustion reaction. This is because combustion reactions typically involve a fuel (SO2) reacting with oxygen (O2) to form a combustion product (SO3) with the release of heat and light energy.
SO2 + H20 --> H2SO3 sulphurous acid is not very stable though # The forest school, the forest school is wonderful the forest school is wonderful its filled with beer and Viagra the forest school is wonderful!!! #
In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
K2CO3 s -> K2O s plus CO2 g 2SO3 g -> 2SO2 g plus O2 g
The chemical equation for the reaction of sulfur and oxygen to form sulfur trioxide is: 2S + 3O2 -> 2SO3
Its balancing is very simple, 2SO2 + O2 = 2SO3
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
1,8 moles of oxygen are necessary.