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What is A stone is thrown upward with an initial velocity of 6m s What maximum height will the stone reach?
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∙ 13y ago
To find the maximum height, we can use the kinematic equation: ( h = \frac{v^2}{2g} ), where ( h ) is the maximum height, ( v ) is the initial velocity (6 m/s in this case), and ( g ) is the acceleration due to gravity (approximately 9.81 m/s(^2)). Plugging in the values, we get ( h = \frac{6^2}{2*9.81} \approx 1.83 ) meters. Therefore, the stone will reach a maximum height of approximately 1.83 meters.
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What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
What is the instantaneous velocity at maximum height when something is thrown straight up?
The instantaneous velocity at the maximum height is zero because the object momentarily stops moving before falling back down due to gravity.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
An object is thrown vertically upward when does it reach maximum height?
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
What is the instantaneous velocity at maximum height when something is thrown straight up?
The instantaneous velocity at the maximum height is zero because the object momentarily stops moving before falling back down due to gravity.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
What is displacement if a ball is thrown up with certain velocity it attains maximum height and comes back to the thrower?
The displacement of the ball from when it was thrown to when it returns to the thrower is zero, as the ball has completed a full round trip back to its initial position. Displacement is a vector quantity that measures the change in position from the initial point to the final point.
What is the maximum height achieved if a 0.800kg mass is thrown straight up with an initial speed of 30.0Ms-1?
The maximum height reached can be calculated using the formula h = (v^2) / (2g), where v is the initial velocity and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values gives h = (30^2) / (2*9.81) = 45.9 meters.
What height is reached by a 4.0kg ball that is thrown vertically up into the air with an initial velocity of 8.5ms1 if by the time it is height (h) metres above the starting point it has a velocity of?
Height reached = 3.7 metres.The mass of the ball is not really relevant.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
What happens when two objects of different mass is thrown up. which will reach maximum height if both are thrown with same velocity?
If you ignore air resistance, then they will reach their maximum height at the same time. In order not to ignore air resistance, you would need to know their shapes.
How high can a ball go?
The maximum height a ball can reach is dependent on factors such as initial velocity, launch angle, air resistance, and gravity. In a vacuum with no air resistance, the ball will continue to rise until gravity slows it down and makes it come back down.
