In beta decay equations, e- refers to an electron (in beta-), and e+ refers to a positron (in beta+).
Not asked, but answered for completeness, ve refers to the electron neutrino that accompanies the positron, and v-e refers to the electron antineutrino that accompanies the electron.
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The "e" in beta decay equations represents an electron. In beta decay, a neutron in the nucleus is converted into a proton, releasing an electron and an antineutrino (or a positron and a neutrino in positron decay).
In radioactive elements always give alpha, beta and gamma rays. Here beta is negative charge ray .
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
β0/-1e
The beta decay of uranium-237 can be represented by the equation: (^{237}{92}U \to ^{237}{93}Np + e^- + \bar{\nu_e}) where (^{237}{92}U) decays into (^{237}{93}Np), an electron (e^-), and an electron antineutrino (\bar{\nu_e}).
The symbol used to represent the electric field in equations is ( \vec{E} ).
The equation for alpha decay of thorium-228 is 228Th -> 224Ra + 4He, where thorium-228 decays into radium-224 by emitting an alpha particle (helium nucleus). The equation for beta decay of aluminum-28 is 28Al -> 28Si + e + v, where aluminum-28 decays into silicon-28 by emitting a beta particle (electron) and an antineutrino.