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"Ln" in that equation is the "natural logarithm" of a number.
The "common logarithm" ... log(x) ... is the logarithm of 'x' to the base of 10.
The "natural logarithm" ... ln(x) ... is the logarithm of 'x' to the base of 'e'.
'e' is an irrational number, known, coincidentally, as the "base of natural logarithms".
It comes up in all kinds of places in math, physics, electricity, and engineering, especially in
situations where the speed of something depends on how far it still has to go to its destination.
'e' is roughly 2.7 1828 1828 45 90 45 ... (rounded)
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How do you calculate actual vapour pressure?
Actual vapor pressure can be calculated using the Antoine equation, which is a function of temperature and constants specific to the substance of interest. The equation is: ln(P) = A - (B / (T + C)), where P is the actual vapor pressure, T is the temperature in Kelvin, and A, B, and C are substance-specific constants.
What are the two sources of e?
The two sources of e are through the natural log function, ln(x), and as the base of the exponential function, e^x.
What is the simple formula in calculating the half life of protactinium-234?
The formula for calculating the half-life of a radioactive substance is t1/2 = (ln(2) / λ), where t1/2 is the half-life, ln is the natural logarithm, and λ is the decay constant. For protactinium-234, the decay constant (λ) is 2.53 x 10^-6 per year. Plug in this value into the formula to calculate the half-life of protactinium-234.
For ideal gas calculate helmholtz free energy?
The Helmholtz free energy for an ideal gas is given by the formula: A = -nRTln(V/n) where A is the Helmholtz free energy, n is the number of moles of gas, R is the gas constant, T is the temperature in Kelvin, and V is the volume of the gas. The negative sign indicates that the Helmholtz free energy decreases as the volume of the gas increases at constant temperature and pressure.
How to calculate helmholtz free energy for ideal gas?
The Helmholtz free energy (A) for an ideal gas can be calculated using the equation (A = -RT \ln(Z)), where (R) is the ideal gas constant, (T) is the temperature in Kelvin, and (Z) is the partition function of the ideal gas. The partition function for an ideal gas is given by (Z = V \left(\frac{2\pi mkT}{h^2}\right)^{3/2}), where (V) is the volume, (m) is the mass of a gas molecule, (k) is the Boltzmann constant, and (h) is the Planck constant.
Which logarithmic equation is equivalent to the exponential equation below ea 60?
ln 60 = a
What exponential equation is equivalent to the logarithmic equation e exponent a equals 47.38?
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
What is the given logarithmic equation for lnx2.35?
If the equation was ln(x) = 2.35 then x = 10.4856, approx.
How do you find value ln 2.33?
To find ln 2.33, you need a calculator. It is the solution of the equation e^x = 2.33. ln 2.33 = 0.84586 (using a calculator)
How do you solve this logarithmic equation ln x equals 5?
In the equation ln(x) = 5, the solution is x = (about) 148.4. To solve, simply raise e to the power of both sides and reduce... ln(x) = 5 eln(x) = e5 x = 148.4
If you have a number with the exponent x how do you find the answer?
Take the natural logarithm (ln) of both sides of the equation to cancel the exponent (e). For example, ify=Aexlog transform both sides and apply the rules of logarithms:ln(y)=ln(Aex)ln(y)=ln(A)+ln(ex)ln(y)=ln(A)+xrearrange in terms of x:x=ln(y)-ln(A), or more simplyx=ln(y/A)
What is the equation for exponential interpolation?
The correct formula for exponential interpolation is: y =ya*(yb/ya)^[(x-xa)/(xb-xa)], xa<x<xb and also, x=xa*[ln(yb)-ln(y)]/[ln(yb)-ln(ya)]+xb*[ln(y)-ln(ya)]/[ln(yb)-ln(ya)], ya<y<yb
How do you solve this logarithmic equation 3x plus 7 equals 20?
To be logarithmic the equation would be, ( otherwise just linear ) 3x + 7 = 20 subtract 7 from each side 3x = 13 now, you know the answer is between x = 2 and x = 3, so I use natural logs both sides ln(3x) = ln(13) as this is a logarithmic operation you can bring down the x in front of the ln sign on the left x ln(3) = ln(13) divideboth sides by ln(3) x = ln(13)/ln(3) ( not ln(13/3)!!!!! ) x = 2.334717519 -------------------------check in original equation 3(2.334717519) + 7 = 20 13 + 7 = 20 20 = 20 --------------checks
What does NN LN stand for in short hand rule?
yes
What is the dervative of x pwr x pwr x?
For the function: y = x^x^x (the superscript notation on this text editor does not work with double superscripts) To solve for the derivative y', implicit differentiation is needed. First, the equation must be manipulated so there are no x's raised to x's on the right side of the equation. So, both sides of the equation must be input into a natural logarithm, wherein we can use the properties of logarithms to remove the superscripted powers of the right side: ln(y) = ln(x^x^x) ln(y) = xxln(x) ln(y)/ln(x) = xx ln(ln(y)/ln(x)) = xln(x) eln(ln(y)/ln(x)) = exln(x) ln(y)/ln(x) = exln(x) ln(y) = ln(x)exln(x) Now there are no functions raised to functions (x's raised to x's). Deriving this equation yields: (1/y)(y') = ln(x)exln(x)(x(1/x) + ln(x)) + exln(x)(1/x) = ln(x)exln(x)(1 + ln(x)) + exln(x)(1/x) = exln(x)(ln(x)(1+ln(x)) + (1/x)) Solving for y' yields: y' = y[exln(x)(ln2(x) + ln(x) + (1/x))] or y = xx^x ln(y) = ln(x)x^x ln(y) = xxln(x) ln(y) = exlnxln(x) y'/y = exlnx[ln(x) + 1)ln(x) + exlnx(1/x) y' = y[exlnx(ln2(x) + ln(x) + 1/x)] y' = xx^x[exlnx(ln2(x) + ln(x) + 1/x)]
How do you solve this logarithmic equation -3 plus ln x equals 5?
-3 + ln(x) = 5 ln(x) = 8 eln(x) = e8 x = e8 x =~ 2981
How do I write an equation for a sequence that isn't linear or exponential?
A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)
