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F = ma, 1N = 1kg(m/s^2)

65 N = 10kg * a

a = 65N / 10kg

a = 6.5 m/s^2

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Marcus Rivera

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You can use Newton's second law of motion, which states that acceleration is equal to the net force acting on an object divided by its mass. In this case, acceleration = net force / mass, so acceleration = 65 N / 10 kg = 6.5 m/s^2.

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Q: What formula would you use to find the acceleration of a 10kg being pushed by a force of 65 N?
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How do you find the acceleration of a pushed object?

You can find the acceleration of a pushed object by dividing the net force acting on the object by its mass, using the formula a = F/m, where a is the acceleration, F is the net force, and m is the mass of the object.


What will be the acceleration Of a 10kg boulder being pushed by a force of 65N?

To find the acceleration, you can use the formula F = ma, where F is the force applied, m is the mass of the object (10 kg), and a is the acceleration. Rearranging the formula to solve for acceleration gives a = F/m. Plugging in the values gives a = 65N / 10kg = 6.5 m/s^2. Therefore, the acceleration of the boulder will be 6.5 m/s^2.


What is the formula for force and acceleration?

The formula for force is F = ma, where F represents force, m is mass, and a is acceleration. For acceleration, the formula is a = F/m, where a is acceleration, F is force, and m is mass.


What is the accleration of a 5 kg mass pushed by a 10 newtons force?

The acceleration of the 5 kg mass pushed by a 10 N force can be calculated using the formula: acceleration = force / mass. Plugging in the values, we get acceleration = 10 N / 5 kg = 2 m/s^2. Therefore, the acceleration of the mass would be 2 m/s^2.


What is the acceleration of a 3 kg ball pushed with 15n force?

The acceleration of the 3 kg ball pushed with a 15 N force can be calculated using Newton's second law: F = ma. Rearranging the formula to solve for acceleration, we have a = F/m. Plugging in the values, we get a = 15 N / 3 kg = 5 m/s^2. Hence, the acceleration of the 3 kg ball pushed with a 15 N force is 5 m/s^2.