The physical quantity measured under a speed-time graph is acceleration. This is because acceleration is represented by the gradient of the graph, where a steeper gradient indicates a higher acceleration.
Acceleration provides information about how an object's velocity is changing over time. It tells you whether the object is speeding up, slowing down, or changing direction. Accurate knowledge of acceleration is crucial for understanding an object's dynamics and predicting its future motion.
When the distance travelled by a body is directly proportional to time, the body is said to have constant speed. This means that the body covers the same distance in equal intervals of time.
If the car is slowing down, it will travel a shorter distance each second as its velocity decreases. The rate at which the distance changes each second depends on the rate of deceleration of the car.
"Volocify" does not appear to be a recognized term. It may be a misspelling or a niche term used in a specific context. Can you provide more details or context for me to better understand and assist you?
Average speed = Distance travelled/time to travel the distance . Average acceleration = Change of speed/time for the change .
The answer depends on the context: You can find the acceleration if you know any three of : initial velocity, final velocity, time, distance travelled. You can find it if you know the mass and force. You know the two masses and the distance between them (gravitational acceleration).
There are three phases to this calculation:# The initial powered acceleration # The deceleration under gravity to the top of the trajectory # The acceleration under gravity back to the ground Using the equations:a = 2(s - ut)/t2a=(v-vo)/tPhase 1Acceleration (a) = 35m/s2Time (t1) = 35sVelocity(v) = 35 x 35 = 1,225m/sDistance travelled (S1) = 21,437mPhase 2Acceleration (a) = -9.8m/s2Initial Velocity (Vo) = 1,225m/sDistance travelled (S2) = 76,562mTime (t2) = 125sPhase 3Acceleration (a) = 9.8m/s2Distance Travelled (St) = S1 + S2 = 98,000mTime (t3) = 141.4sThus total time = t1 + t2 + t3 = 35 + 125 + 141.4 = 301.4s
This is correct but what they are looking for is Mass. I think its, Speed= Distance Travelled _______________ Time Taken *That means distance travelled (divided) by time taken. Eg. 40km (Divided by) 8 hrs = 5 km/ph
a=s/t, and s=d/t, so if we substitute... a = (d/t)/t --> a = d/t2 You must know both the acceleration and time in order to solve for the distance travelled.
a = (v2 - u2)/2s where a is the acceleration between the initial point in time and the final point in time, u is the initial velocity v is the final velocity s is the distance travelled
The physical quantity measured under a speed-time graph is acceleration. This is because acceleration is represented by the gradient of the graph, where a steeper gradient indicates a higher acceleration.
No, the distance an object travels in unit time is called speed. The distance travelled per unit time in a specified direction is called velocity. The rate of change of velocity is called acceleration.
The distance travelled by an object in a given time is given by:Distance = Speed * TimeAlternatively for an object that is accelerating:Distance = (Speed of object before acceleration is applied * Time) + (0.5 * Acceleration * Time squared)If the object is accelerating from speed zero, the first set of brackets is irrelevant.Also, if the object is falling to the ground, acceleration = 9.81
they travelled by Ferrari
Acceleration provides information about how an object's velocity is changing over time. It tells you whether the object is speeding up, slowing down, or changing direction. Accurate knowledge of acceleration is crucial for understanding an object's dynamics and predicting its future motion.
When the distance travelled by a body is directly proportional to time, the body is said to have constant speed. This means that the body covers the same distance in equal intervals of time.