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If your graph shows velocity on the vertical axis and time on the horizontal axis, then the slope of the graph represents the acceleration.

More specifically, the slope of the graph at a specific point represents the acceleration at that instantaneous point in time.

So if the slope of the graph doesn't change (i.e. the graph is a straight line), then the acceleration is constant and doesn't change over time.

In calculus, this is represented as the derivative: The derivative of velocity with respect to time equals the acceleration.

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15y ago
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5mo ago

The slope of a velocity versus time graph gives acceleration. By calculating the slope of the graph at a particular point, you can determine the acceleration of an object at that specific moment in time.

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14y ago

Acceleration.

The slope of a graph gives the rate of change of one thing with respect to another.

In a velocity time graph, the slope gives the rate of change of velocity with respect to time, that is how velocity changes over time. This is acceleration.

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Q: The slope of velocity versus time graph gives?
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Related questions

Does the slope of a speed-versus-time graph represents acceleration?

No, the slope of a speed-versus-time graph represents the rate of change of speed, not acceleration. Acceleration is represented by the slope of a velocity-versus-time graph.


Is acceleration the slope of the velocitys vs the time graph?

Yes, acceleration is the slope of a velocity versus time graph.


What is a graph of distance-versus-time the slope of the line indicates the of an object?

The graph represents the speed of the object. The slope of the line indicates the object's velocity, with a steeper slope representing a higher velocity and a flatter slope representing a lower velocity.


What does the slope of a curve represent on a velocity-versus-time graph represent?

The slope of the speed/time graph is the magnitude of acceleration. (It's very difficult to draw a graph of velocity, unless the direction is constant.)


What does the slope of distance-versus-time graph represent physically?

instantaneous magnitude of velocity


What does the slope of they curve on a velocity-versus-time graph represent?

The rate of change in accelleration.


How can you use the graph of velocity versus time to estimate the acceleration of the ball?

The acceleration of the ball can be estimated by calculating the slope of the velocity versus time graph. If the graph is a straight line, the slope represents the acceleration. The steeper the slope, the greater the acceleration. If the graph is curved, the instantaneous acceleration can be estimated by finding the slope of the tangent line at a specific point on the curve.


Does the slope of a position time graph represent average velocity or rate of change of velocity?

The slope of a position-time graph represents the average velocity of an object. It does not represent the rate of change of velocity, which would be represented by the slope of a velocity-time graph.


When velocity is changing what is happening to the slope on a position versus time graph?

When velocity is changing, the slope of the position versus time graph represents the velocity at that particular moment. The slope becomes steeper when velocity is increasing and shallower when velocity is decreasing. A horizontal line indicates zero velocity.


Is velocity the slope of the displacement vs time graph true or false?

True. Velocity is the rate of change of displacement with respect to time, which is represented by the slope of the displacement versus time graph.


What does the slope of distance versus time graph represent physically?

The slope of a distance versus time graph represents the speed or velocity of an object. A steeper slope indicates a higher speed, while a gentler slope indicates a slower speed. If the slope is negative, it means the object is moving in the opposite direction.


What does the slope of a distance versus-time graph show about the motion of an object?

the slope show the velocity of the object which show its direction and magnitude.