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Nodes and antinodes are part of a standing wave pattern.

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What is the wavelength of the standing waves if the string is 1.5 m long?

The wavelength of the standing wave on a string that is 1.5 m long can be calculated using the formula: wavelength = 2L/n, where L is the length of the string and n is the number of nodes or antinodes.


How is the wavelength related to the distance between nodes?

A node is a point along a standing wave where the wave has minimal amplitude. The opposite of a node is an antinode, a point where the amplitude of the standing wave is a maximum. These occur midway between the nodes. Examples of a type of boundary could be the attachment point of a string, the closed end of an organ pipe or a woodwind pipe, the periphery of a drumhead, or a transmission line with the end short circuit. In this type, the amplitude of the wave is forced to zero at the boundary, so there is a node at the boundary, and the other nodes occur at multiples of half a wavelength from it: 0, λ/2, λ, 3λ/2, 2λ, ... One wavelength has 3 nodes and 2 antinodes. Between two nodes is the distance of half the wavelegth.


What is the speed of a wave that has a frequency of 250 Hz and a wavelength of 1.2?

we know the equation V=nLv=speed of wave n=frequency L=wavelength here v=? n=250Hz & L=1.2 v=250*1.2 =300m/s


When an wave transfers into a denser medium the reflected wave is what?

When a wave transfers into a denser medium, a portion of the wave is reflected back into the original medium. The reflected wave can have different amplitudes and phases compared to the incident wave depending on the properties of the medium interface.


What is fermi wave vector of fermi gas in one dimension box of length L?

The Fermi wave vector (k_F) of a fermi gas in a one-dimensional box of length L is given by the formula: k_F = n * π, where n is the number density of fermions in the box.

Related Questions

What is the wavelength of the standing waves if the string is 1.5 m long?

The wavelength of the standing wave on a string that is 1.5 m long can be calculated using the formula: wavelength = 2L/n, where L is the length of the string and n is the number of nodes or antinodes.


How is the wavelength related to the distance between nodes?

A node is a point along a standing wave where the wave has minimal amplitude. The opposite of a node is an antinode, a point where the amplitude of the standing wave is a maximum. These occur midway between the nodes. Examples of a type of boundary could be the attachment point of a string, the closed end of an organ pipe or a woodwind pipe, the periphery of a drumhead, or a transmission line with the end short circuit. In this type, the amplitude of the wave is forced to zero at the boundary, so there is a node at the boundary, and the other nodes occur at multiples of half a wavelength from it: 0, λ/2, λ, 3λ/2, 2λ, ... One wavelength has 3 nodes and 2 antinodes. Between two nodes is the distance of half the wavelegth.


With n nodes and b branches a network will have?

With n nodes and b branches a network will have combination are


How many different trees are possible with 10 nodes?

1014 it is. no of different trees possible with n nodes is (2^n)-n thanx


What is the maximum height of a binary tree with a given number of nodes?

The maximum height of a binary tree with 'n' nodes is 'n-1'.


A binary tree with 20 nodes has null branches equals?

A binary tree with n nodes has exactly n+1 null nodes or Null Branches. so answer is 21. MOHAMMAD SAJID


A fully connected network of 6 nodes requires how many links?

let suppose total number of nodes/computers = n the formula will be = n(n-1)/2 e.g = 6(6-1)/2 =15 links.


What is the number of nodes in a complete binary tree of level 5?

If the number of levels is L, the maximum number of nodes N in a binary tree is N = 2L-1. For L = 5, N equates to 31 thus.


In which maximum angular nodes are present?

For an s orbital, there are no angular nodes. For a p orbital, there is 1 angular node. For a d orbital, there are 2 angular nodes. The maximum number of angular nodes is given by n-1, where n is the principal quantum number of the orbital.


How many anti nodes does the n equals 6 have?

As in one wavelength we have two anti-nodes so for 6 wavelengths we will have 12 anti-nodes.


What is the height of a binary tree with n nodes in the worst case?

For the height `h' of a binary tree, for which no further attributes are given than the number `n' of nodes, holds:ceil( ld n)


What is the maximum number of nodes on a given level of a binary tree?

Level N of a binary tree has, at most, 2^N nodes. Note that the root node is regarded as being level 0. If we regard it as being level 1, then level N would have 2^(N-1) nodes at most.