Nodes and antinodes are part of a standing wave pattern.
The wavelength of the standing wave on a string that is 1.5 m long can be calculated using the formula: wavelength = 2L/n, where L is the length of the string and n is the number of nodes or antinodes.
The wavelength of a wave is related to the distance between nodes by the formula λ = 2L/n, where λ is the wavelength, L is the distance between nodes, and n is the mode number. As n increases, the wavelength decreases and the nodes become closer together, while as n decreases, the wavelength increases and the nodes become further apart.
The speed of a wave can be calculated using the formula: speed = frequency x wavelength. Plugging in the values given, the speed of the wave is 300 m/s.
When a wave transfers into a denser medium, a portion of the wave is reflected back into the original medium. The reflected wave can have different amplitudes and phases compared to the incident wave depending on the properties of the medium interface.
The Fermi wave vector (k_F) of a fermi gas in a one-dimensional box of length L is given by the formula: k_F = n * π, where n is the number density of fermions in the box.
The wavelength of the standing wave on a string that is 1.5 m long can be calculated using the formula: wavelength = 2L/n, where L is the length of the string and n is the number of nodes or antinodes.
The wavelength of a wave is related to the distance between nodes by the formula λ = 2L/n, where λ is the wavelength, L is the distance between nodes, and n is the mode number. As n increases, the wavelength decreases and the nodes become closer together, while as n decreases, the wavelength increases and the nodes become further apart.
With n nodes and b branches a network will have combination are
1014 it is. no of different trees possible with n nodes is (2^n)-n thanx
The maximum height of a binary tree with 'n' nodes is 'n-1'.
A binary tree with n nodes has exactly n+1 null nodes or Null Branches. so answer is 21. MOHAMMAD SAJID
let suppose total number of nodes/computers = n the formula will be = n(n-1)/2 e.g = 6(6-1)/2 =15 links.
If the number of levels is L, the maximum number of nodes N in a binary tree is N = 2L-1. For L = 5, N equates to 31 thus.
For an s orbital, there are no angular nodes. For a p orbital, there is 1 angular node. For a d orbital, there are 2 angular nodes. The maximum number of angular nodes is given by n-1, where n is the principal quantum number of the orbital.
As in one wavelength we have two anti-nodes so for 6 wavelengths we will have 12 anti-nodes.
For the height `h' of a binary tree, for which no further attributes are given than the number `n' of nodes, holds:ceil( ld n)
Level N of a binary tree has, at most, 2^N nodes. Note that the root node is regarded as being level 0. If we regard it as being level 1, then level N would have 2^(N-1) nodes at most.