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Does xenon have the tendency to lose or gain electrons in reactions?

it is a noble gas, it doesn't do either one


Does xenon form a monatomic ion?

Yes, xenon can form monatomic ions, known as xenon ions. Xenon can lose electrons to form positively charged xenon ions or gain electrons to form negatively charged xenon ions.


Why is the element xenon unreactive?

Xenon is unreactive because it has a full outer electron shell, making it very stable and reluctant to gain, lose, or share electrons with other elements. This stable electron configuration makes it difficult for xenon to form chemical bonds with other elements, resulting in its inertness.


What chemical bond occurs when atoms lose gain or share electrons?

When atoms lose and gain electrons, an ionic bond will form. When atoms share electrons, a covalent bond will form.


Does Krypton tend to lose, gain, or share its electron?

Krypton tends to neither lose nor gain electrons since it has a full outer electron shell, making it stable.


What is a reason for atoms to not gain lose or share electrons?

This depends on the electronegativity of atoms.


When molecules are formed atoms share or loose electrons?

To form a molecule, atoms can share, lose, and gain electrons


Do atoms of a covalent bond lose or gain elecrons?

do atoms of a covalent bond lose r share electrons


Will radon lose gain or share electrons?

Typically no because it is a noble gas and has a full octet.


What happens to bonds between atoms when chemical change occur?

An atom can gain, lose, or share.


Do atoms lose and gain electrons when a new substance is forming?

Some atoms lose electrons, some gain electrons, and some share electrons depending on what elements are involved and what compound is forming.


Do atoms join by a covalent bond do not gain or lose electrons?

Atoms that join by a covalent bond share electrons but do not gain or lose them. In a covalent bond, the electrons are shared between the atoms, creating a stable electron configuration for both atoms involved.