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If you throw a 0.1 kg ball straight up with an initial speed of 29 ms how high will it climb?
Wiki User
∙ 6y ago
To find the maximum height reached by the ball, you can use the kinematic equation (v_f^2 = v_i^2 + 2aΔy) where (v_f = 0), (v_i = 29 m/s), (a = -9.8 m/s^2) (acceleration due to gravity), and solve for (Δy). Substituting the values gives (0 = 29^2 - 29.8Δy), solving for Δy gives Δy ≈ 42 meters.
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To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.
When a ball is throw upward how does the height reached by the ball depend on its initial speed?
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
How can you throw a projectile so that it has nonzero speed at the top of trajectory?
To achieve nonzero speed at the top of the trajectory, you should throw the projectile upward with an initial velocity greater than zero. This will allow the projectile to continue moving upward even at the top of its trajectory before it begins to fall back down due to gravity.
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If you are moving at a speed of ceratin speed and there is no force trying to slow you down, and there is no force trying to speed you up. Then there is zero acceleration. An example would be : an object in out in space, if you throw a object away from you the object will float away, since there is no force working on the object after you throw it the object is moving away in a locked speed from you, but have zero acceleration because there is no force affecting the object
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The height reached by a ball thrown upward depends on the initial velocity of the throw, the force of gravity acting on the ball, and air resistance. The height reached is determined by balancing the initial kinetic energy of the throw with the potential energy gained as the ball moves upward against the force of gravity.
How can you throw a projectile so that it has zero speed at the top?
To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.
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When a ball is throw upward how does the height reached by the ball depend on its initial speed?
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
How can you throw a projectile so that it has nonzero speed at the top of trajectory?
To achieve nonzero speed at the top of the trajectory, you should throw the projectile upward with an initial velocity greater than zero. This will allow the projectile to continue moving upward even at the top of its trajectory before it begins to fall back down due to gravity.
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