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The extension of a spring depends on its stiffness, which is given by its spring constant. If the spring constant is known, you can use Hooke's Law (F = kx) to calculate the stretch of the spring. For example, if the spring constant is 100 N/m, a 1 kg weight would stretch the spring by 0.1 meters (10 cm).
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If a certain spring stretches 4cm when a load of 10N is suspended from it how much will the spring stretch if it is cut in half and 10N is suspended from it?
If the spring is cut in half, its stiffness will increase and it will stretch less for the same load. The new stretch will depend on the new stiffness of the spring. Without knowing the exact stiffness of the original spring and the new one, it is difficult to determine the exact stretch without calculations.
If a certain spring stretches 10 cm when a load of 12 N is suspended from it how much will the spring stretch if it is cut in half and 12 N is suspended from it?
If the spring is cut in half, it will have half the original stiffness. So, when 12 N is suspended from the cut spring, it will stretch twice as much as before - 20 cm.
A spring that stretches 5.0 cm when a load of 11 N is suspended from it how much will the spring stretch if an identical spring supports the load?
If the two springs are identical, the second spring will also stretch by 5.0 cm when a load of 11 N is suspended from it. This is because the behavior of springs is determined by their stiffness or spring constant, which is the same for identical springs.
How much force is required to stretch the spring 49 inches?
The amount of force required to stretch a spring by 49 inches depends on the stiffness or spring constant of the spring. The formula to calculate this force is F = k * x, where F is the force, k is the spring constant, and x is the displacement of the spring (in this case, 49 inches). Without knowing the spring constant, the force required cannot be determined.
If a force of 90 N stretches a spring 1m beyond its natural lengthhow much work does it take to stretch the spring 5m beyond its natural length?
The work done to stretch the spring is given by the formula W = (1/2)kx^2, where k is the spring constant and x is the displacement. First, calculate the spring constant using Hooke's Law (F = kx). Then, use the calculated k value to find the work done to stretch the spring 5m beyond its natural length.
How much a 5-pound weight would stretch the spring?
It depends on spring energy or spring strength
What is the length of the spring when a weightof 10n hangs from it?
depends on the initial length of the spring, and how much force is required to stretch the spring
What is the spring constant of a spring?
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
If a certain spring stretches 4cm when a load of 10N is suspended from it how much will the spring stretch if it is cut in half and 10N is suspended from it?
If the spring is cut in half, its stiffness will increase and it will stretch less for the same load. The new stretch will depend on the new stiffness of the spring. Without knowing the exact stiffness of the original spring and the new one, it is difficult to determine the exact stretch without calculations.
If a certain spring stretches 10 cm when a load of 12 N is suspended from it how much will the spring stretch if it is cut in half and 12 N is suspended from it?
If the spring is cut in half, it will have half the original stiffness. So, when 12 N is suspended from the cut spring, it will stretch twice as much as before - 20 cm.
A certain spring stretches 6 cm when a load of 15 N is suspended from it How much will the spring stretch if 30 N is suspended from it and it doesn't reach its elastic limit?
It will stretch 6 cm.
A spring that stretches 5.0 cm when a load of 11 N is suspended from it how much will the spring stretch if an identical spring supports the load?
If the two springs are identical, the second spring will also stretch by 5.0 cm when a load of 11 N is suspended from it. This is because the behavior of springs is determined by their stiffness or spring constant, which is the same for identical springs.
Does an extension spring behave according to Hooke's law?
Yes it does, unless you stretch it so much that it yields
How much force is required to stretch the spring 49 inches?
The amount of force required to stretch a spring by 49 inches depends on the stiffness or spring constant of the spring. The formula to calculate this force is F = k * x, where F is the force, k is the spring constant, and x is the displacement of the spring (in this case, 49 inches). Without knowing the spring constant, the force required cannot be determined.
If a force of 90 N stretches a spring 1m beyond its natural lengthhow much work does it take to stretch the spring 5m beyond its natural length?
The work done to stretch the spring is given by the formula W = (1/2)kx^2, where k is the spring constant and x is the displacement. First, calculate the spring constant using Hooke's Law (F = kx). Then, use the calculated k value to find the work done to stretch the spring 5m beyond its natural length.
How much will the spring be stretched 25kg of 4500Nm?
To calculate the spring stretch, you need to use Hooke's Law formula which states F = kx, where F is force, k is the spring constant, and x is the displacement/stretch of the spring. Rearranging the formula to solve for x, you get x = F/k. Given force (4500 N) and mass (25 kg), you can calculate the force as F = m*g, where m is the mass and g is the acceleration due to gravity (9.81 m/s^2). Then, you can calculate the spring constant using Hooke's Law formula with the given force and stretch. Subsequently, use this spring constant to determine the stretch of the spring by rearranging the Hooke's Law formula.
How much energy can be stored in a spring with a spring constant of 500Nm if its maximum possible stretch is 20cm?
The maximum potential energy stored in the spring can be calculated using the formula ( E = \frac{1}{2}kx^2 ), where ( k = 500 N/m ) is the spring constant and ( x = 0.2 m ) is the maximum stretch. Plugging in these values, the stored energy would be ( E = \frac{1}{2} \times 500 \times (0.2)^2 = 10 J ).
