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Work = (force) x (distance)

(300 poundforce) x (60-ft) = 18,000 foot-pounds

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13y ago
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1mo ago

The work done in lifting the load of bricks can be calculated using the formula: work = force x distance. In this case, the force is the weight of the load (300 lbs) and the distance is the height it was lifted (60 feet). Therefore, the work done is 18,000 foot-pounds (300 lbs x 60 feet).

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Q: How much work is done in lifting a 300-lb load of bricks to a height of 60 feet on a building under construction?
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The work done in lifting 30 kg of bricks to a height of 20 m on a building under construction is?

The work done in lifting 30 kg of bricks to a height of 20 m would be ( W = mgh = 30 kg \times 9.8 m/s^2 \times 20 m = 5880 , \text{Joules} ). The work done is 5880 Joules.


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Two examples of where the The Work at Height Regulations may apply to lifting operations including safety equipment and closely monitoring the lift. These simple steps can go a long way to prevent accidents or injuries.


How much work is done in lifting a 50kg object to height of 5m?

The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).


How much work is done to lift 40kg of bricks to a height of 10m?

The work done to lift 40kg of bricks to a height of 10m can be calculated using the formula: Work = Force x Distance. The force required to lift the bricks is equal to the weight, which is mass x gravity (40kg x 9.8m/s^2). Plug these values into the formula to find the work done.


Describe the effect that height has on the force and energy needed to lift an object?

The force needed to lift an object is directly proportional to its weight, not its height. However, lifting an object at a greater height requires more energy due to the work done against gravity over a longer distance. So, height affects the energy required to lift an object but not the force needed.

Related questions

The work done in lifting 30 kg of bricks to a height of 20 m on a building under construction is?

The work done in lifting 30 kg of bricks to a height of 20 m would be ( W = mgh = 30 kg \times 9.8 m/s^2 \times 20 m = 5880 , \text{Joules} ). The work done is 5880 Joules.


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