Wiki User
∙ 6y agoYou would need 20,920 Joules of heat to raise the temperature of 1kg of water by 5°C. This value is calculated using the specific heat capacity of water, which is 4186 J/kg°C.
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Iron would require a greater amount of heat to raise its temperature compared to water. This is because iron has a higher specific heat capacity, meaning it takes more heat energy to increase its temperature by 1 degree Celsius compared to water.
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. To raise the temperature of one kilogram (1000 grams) of water by one degree Celsius, it would require approximately 4180 Joules of heat energy.
It takes approximately 4186 joules to raise the temperature of one liter of water to its boiling point and an additional 2260 joules to convert it from liquid to vapor. So, in total, around 6446 joules are required to boil one liter of water at normal atmospheric pressure.
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Iron would require a greater amount of heat to raise its temperature compared to water. This is because iron has a higher specific heat capacity, meaning it takes more heat energy to increase its temperature by 1 degree Celsius compared to water.
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. To raise the temperature of one kilogram (1000 grams) of water by one degree Celsius, it would require approximately 4180 Joules of heat energy.
It takes approximately 4186 joules to raise the temperature of one liter of water to its boiling point and an additional 2260 joules to convert it from liquid to vapor. So, in total, around 6446 joules are required to boil one liter of water at normal atmospheric pressure.
The specific heat capacity of water is 4.18 J/g°C. Therefore, it would require 4186 Joules (4.18 x 1000 grams) of energy to raise the temperature of 1 kilogram of water by 1 degree Celsius.
It takes approximately 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Since 1 liter of water is equivalent to 1000 grams, it would require 1000 calories to raise the temperature of 1 liter of water by 1 degree Celsius.
To calculate the energy required to raise the temperature of water, you can use the formula: energy = mass x specific heat capacity x temperature change. The specific heat capacity of water is approximately 4.18 J/g°C. Plugging in the values, the energy required would be 10.0 g x 4.18 J/g°C x 25.0°C = 1045 Joules.
The process you are referring to is called water having a specific heat capacity of 4.184 J/g°C. This means that it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius. In this case, to gain 2260 joules of energy, it would take approximately 540.3 grams of water.
The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.
42 J
10ml's of water is equal to 10cm3 of water. 10cm3 of water has a mass of 10g. The specific heat of water is 4.134 J/K. The change in temperature is 1 degree Kelvin. Use Q=mC∆T which means Heat= (Mass)(Specific Heat)(Change in Temperature) Q= (10)(4.134)(1) Q=(10)(4.134) Q=41.34 Joules