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The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.

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Q: How much energy would be required to melt 32.0 g of ice?
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How much energy is required to melt to kilograms of copper?

The energy required to melt 1 kg of copper at its melting point of about 1084°C is approximately 205 kJ. Therefore, to melt 2 kg of copper, you would need around 410 kJ of energy.


How much energy is required to melt 2kg of gold?

To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.


How much energy is required to melt 1.5 kg of gold?

The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.


How much energy is required to melt 1.5 kg gold?

The specific heat of gold is 0.129 J/g°C, and its melting point is 1064°C. The energy required to melt 1.5 kg of gold can be calculated using the formula: Energy = mass * specific heat * temperature change. So, the energy required would be approximately 2.3 x 10^6 Joules.


How much ergy is required to melt 2 kg of gold?

The specific heat capacity of gold is 0.128 J/g°C, and the heat of fusion of gold is 63 J/g. To calculate the energy required to melt 2 kg of gold, you would first need to convert the mass to grams (2000 g). The energy required would be the sum of the energy needed to raise the temperature from the melting point to the melting point and the energy needed for the phase change.