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How much acceleration does a 747 jumbo jet of mass 30000 kg experience when the thrust for each of its four engines is 30000 N?
Girlneedinghelp
F = M A
A = F / M
Until air-resistance begins to have a significant influence . . .
A = (4 x 30,000)/(30,000) = 4 meters/sec2 = roughly 0.4 G
Wiki User
∙ 12y ago
The total thrust from all four engines is 120,000 N (30,000 N per engine). To calculate acceleration using Newton's second law (F=ma), we divide the total thrust by the mass of the jet: 120,000 N / 30,000 kg = 4 m/s^2. Therefore, the acceleration experienced by the 747 jumbo jet is 4 m/s^2.
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How much acceleration does a 747 jumbo jet of mass 29000 kg experience in takeoff when the thrust for each of four engines is 30000 N?
To find the acceleration of the 747 jet during takeoff, we need to calculate the total thrust generated by all four engines. The total thrust is 4 times the thrust of each engine, which equals 120,000 N. Then, we can use Newton's second law (F=ma) to calculate the acceleration, which is 120,000 N divided by the mass of the plane (29,000 kg), resulting in an acceleration of approximately 4.14 m/s^2.
How much acceleration does a 747 jumbo jet of mass 29600 kg experience in takeoff when the thrust for each of four engines is 30000 N?
To find the acceleration, we first need to calculate the total thrust produced by all four engines. Since each engine produces 30,000 N of thrust, the total thrust is 4 * 30,000 = 120,000 N. The acceleration can be calculated using Newton's second law, F = ma, where F is the total thrust (120,000 N) and m is the mass of the jet (29,600 kg). Plugging in the values, we get a = 120,000 N / 29,600 kg ≈ 4.05 m/s^2.
How much acceleration does a 747 jumbo jet of mass 30000 kg experience in takeoff when the thrust for each of four engines is 30000n?
The total thrust produced by all four engines is 120,000 N (30,000 N x 4). To calculate acceleration, we use Newton's second law: acceleration = total force / mass. Plugging in the numbers, the acceleration experienced during takeoff is 4 m/s^2 (120,000 N / 30,000 kg).
How much acceleration does a 747 jumbo jet of mass 30000kg experience when the thrust for each of its four engines is 30000 N?
The total thrust from all four engines is 120,000 N. To find the acceleration, we divide the total thrust by the mass of the jet: 120,000 N / 30,000 kg = 4 m/s^2. Therefore, the 747 jumbo jet would experience an acceleration of 4 m/s^2.
How many 30kg in g?
There are 30,000 grams in 30 kilograms.
How much acceleration does a 747 jumbo jet of mass 29000 kg experience in takeoff when the thrust for each of four engines is 30000 N?
To find the acceleration of the 747 jet during takeoff, we need to calculate the total thrust generated by all four engines. The total thrust is 4 times the thrust of each engine, which equals 120,000 N. Then, we can use Newton's second law (F=ma) to calculate the acceleration, which is 120,000 N divided by the mass of the plane (29,000 kg), resulting in an acceleration of approximately 4.14 m/s^2.
How much acceleration does a 747 jumbo jet of mass 29600 kg experience in takeoff when the thrust for each of four engines is 30000 N?
To find the acceleration, we first need to calculate the total thrust produced by all four engines. Since each engine produces 30,000 N of thrust, the total thrust is 4 * 30,000 = 120,000 N. The acceleration can be calculated using Newton's second law, F = ma, where F is the total thrust (120,000 N) and m is the mass of the jet (29,600 kg). Plugging in the values, we get a = 120,000 N / 29,600 kg ≈ 4.05 m/s^2.
How much acceleration does a 747 jumbo jet of mass 30000 kg experience in takeoff when the thrust for each of four engines is 30000n?
The total thrust produced by all four engines is 120,000 N (30,000 N x 4). To calculate acceleration, we use Newton's second law: acceleration = total force / mass. Plugging in the numbers, the acceleration experienced during takeoff is 4 m/s^2 (120,000 N / 30,000 kg).
How much acceleration does a 747 jumbo jet of mass 30000kg experience when the thrust for each of its four engines is 30000 N?
The total thrust from all four engines is 120,000 N. To find the acceleration, we divide the total thrust by the mass of the jet: 120,000 N / 30,000 kg = 4 m/s^2. Therefore, the 747 jumbo jet would experience an acceleration of 4 m/s^2.
What is 29 percent of 30000?
29% of 30000 = 29% * 30000 = 0.29 * 30000 = 8700
What is 2 percent of 30000?
2% of 30000 = 2% * 30000 = 0.02 * 30000 = 600
What is 7 percent of 30000?
7 % of 30000 = 7/100 * 30000 = 0.07 * 30000 = 2100
How much would 30 percent of 30000 be?
30% of 30000= 30% * 30000= 0.30 * 30000= 9000
what is 10000+20000?
30000
How do you write 30000 as a fraction?
30000 or 30000 over 1 _____ 1
What is 25987 rounded to the nearest ten thousand?
30,000.
What is 1 percent of 300.00?
1 percent of 30000 = 3001% of 30000= 1% * 30000= 0.01 * 30000= 300
