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To calculate the amount of NH3 needed to react with 21 grams of CH3OH, you first need to balance the chemical equation for the reaction. Then, you convert the mass of CH3OH to moles and use the mole ratio from the balanced equation to determine the moles of NH3 required. Finally, convert the moles of NH3 to grams using the molar mass of NH3.
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How many grams of antimatter are needed to react with 5 g of matter?
Exactly 5 grams of antimatter will completely annihilate 5 grams of matter, producing an enormous shower of high energy gamma rays. In total a mass of 10 grams will be converted to the equivalent amount of energy.
How many grams of bromine are required to completely react with 22.1 g of titanium?
The molar mass of titanium is 47.87 g/mol and the molar mass of bromine is 79.90 g/mol. Titanium reacts with two moles of bromine, so you would need 2 moles of bromine per mole of titanium. Using the molar masses of both elements, you can calculate the grams of bromine needed to react with 22.1 g of titanium.
What is the equilvalent weight?
Equivalent weight is the mass of a substance that will react with or replace one mole of hydrogen ions (H+) in an acid-base reaction or one mole of electrons in a redox reaction. It is used in stoichiometry calculations to determine the amount of a substance needed for a reaction.
How many grams of Fe3O4 are required to react completey with 300 grams of H2?
The balanced chemical equation for the reaction between Fe3O4 and H2 is: Fe3O4 + 4H2 -> 3Fe + 4H2O From the equation, it can be seen that 1 mole of Fe3O4 reacts with 4 moles of H2. Calculate the moles of H2 in 300g, then use the mole ratio to find the moles of Fe3O4 needed. Finally, convert the moles of Fe3O4 to grams using its molar mass to determine the amount required.
How many grams of oxygen are needed to react with 2.5 grams of dihydrogen sulfide?
The molar ratio of oxygen to dihydrogen sulfide in the reaction is 3:1. First, find the number of moles of dihydrogen sulfide by dividing its mass by its molar mass. Then, use the mole ratio to calculate the moles of oxygen needed. Finally, convert the moles of oxygen to grams.
Balanced equation for methanol and water?
Methanol (CH3OH) reacts with water (H2O) to form methyl alcohol (CH3OH) and a hydroxide ion (OH-). The balanced equation for this reaction is: CH3OH + H2O -> CH3OH + OH-
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many grams of are needed to react with 3.18 of?
cannot answer without more info.
How many grams of antimatter are needed to react with 5 g of matter?
Exactly 5 grams of antimatter will completely annihilate 5 grams of matter, producing an enormous shower of high energy gamma rays. In total a mass of 10 grams will be converted to the equivalent amount of energy.
How many moles of O2 are required to react with 23.5 moles of methanol?
The balanced chemical equation for the reaction between methanol and oxygen is: 2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O From the equation, 3 moles of O2 are required to react with 2 moles of CH3OH. Therefore, to react with 23.5 moles of CH3OH, you would need 35.25 moles of O2.
How many grams of silver nitrate are needed to react with 50 grams of sodium chloride?
You need 145,337 g silver nitrate.
What is the structural formula of c3h7cooh ch3oh-c3h7cooch3 hoh?
The structural formula of C3H7COOH is CH3CH2COOH (propionic acid). The structural formula of CH3OH-C3H7COOCH3 is CH3OH + CH3CH2COOCH3 (methyl propionate). H2O (water) is produced when these two compounds react together.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
If you start with 32 grams of CH4 and react it with O2 to form 88 grams CO2 and 72 grams H2O. How much O2 in grams was consumed?
128 g of oxygen are needed.
How many grams of iron will be needed to react completely with an excess of oxygen to form 40 grams of iron3 oxide?
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
