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That depends on whether you are talking about 1 °C or 1 °F. It also depends somewhat on the type of steel.

Warming carbon steel by 1 °C requires about 0.49 J/kg of steel.

Warming 316 stainless steel 1 °C requires about 0.45 J/kg of steel.

To find the answer for 1 °F, multiply the values by 5/9.

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āˆ™ 12y ago
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āˆ™ 6mo ago

The specific heat capacity of steel is about 0.45 J/gĀ°C. So, it would take 0.45 joules of energy to warm 1 gram of steel by 1 degree Celsius.

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How many watts are required to raise 1 gallon of water 1 degree F?

1 gallon of water is 4540 cc and 1 degree F is 0.555 degrees C, so raising 4540 cc of water by 0.555 degree C would take 4540x0.555 calories, or 2520 calories. Multiply by 4.2 to convert to joules which gives 10590 joules. Therefore the energy required is 10590 joules which is the same as 10590 watt-seconds. That could be done by 100 watts in 105.9 seconds, or 1000 watts in 10.59 seconds.


What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?

The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.


How much joules does it take to heat water to 100 degrees?

To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.


How long does it take to perform 475 Joules of work with 25 watts of power?

To calculate the time it takes to perform 475 Joules of work with 25 watts of power, you use the formula: time = work / power. In this case, time = 475 Joules / 25 watts = 19 seconds. So, it will take 19 seconds to perform 475 Joules of work with 25 watts of power.


How long does it take to perform 500 Joules of work with 25 watts of power?

To find the time taken to perform 500 joules of work at a power of 25 watts, you divide the work by the power. In this case, 500 Joules / 25 watts = 20 seconds. Therefore, it would take 20 seconds to perform 500 Joules of work with 25 watts of power.

Related questions

How many joules does it take to warm water by 1 degree?

It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.


How many watts are required to raise 1 gallon of water 1 degree F?

1 gallon of water is 4540 cc and 1 degree F is 0.555 degrees C, so raising 4540 cc of water by 0.555 degree C would take 4540x0.555 calories, or 2520 calories. Multiply by 4.2 to convert to joules which gives 10590 joules. Therefore the energy required is 10590 joules which is the same as 10590 watt-seconds. That could be done by 100 watts in 105.9 seconds, or 1000 watts in 10.59 seconds.


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If by "boil" you mean have it all evaporate, that takes MUCH more energy. For example, to increase the temperature of one gram of water from 20 to 100 degrees Celsius, you need 4.2 joules/gram/degree times 80 degrees = about 336 joules; then, to evaporate all the water, you need an additional 2257 joules.


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The process you are referring to is called water having a specific heat capacity of 4.184 J/gĀ°C. This means that it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius. In this case, to gain 2260 joules of energy, it would take approximately 540.3 grams of water.


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