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∙ 9y agoIt takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
To calculate the joules needed to raise the temperature of water, you can use the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, calculate the mass of 2.0 liters of water in grams (1 mL of water = 1g), then use the specific heat capacity of water (4.18 J/g°C) to find the total heat energy required. The final step is to calculate the joules needed using the formula, remembering that 1 calorie is equivalent to 4.18 joules.
To calculate the heat needed to change the temperature of water, you can use the specific heat capacity of water, which is 4.18 J/g°C. If you're specifying the temperature change, you would use the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass of the water (40 g), c is the specific heat capacity of water, and ΔT is the temperature change.
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
42 J
134 joules. You're very welcome for answering your question.
8.200 J
To calculate the joules needed to raise the temperature of water, you can use the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, calculate the mass of 2.0 liters of water in grams (1 mL of water = 1g), then use the specific heat capacity of water (4.18 J/g°C) to find the total heat energy required. The final step is to calculate the joules needed using the formula, remembering that 1 calorie is equivalent to 4.18 joules.
To calculate the heat needed to change the temperature of water, you can use the specific heat capacity of water, which is 4.18 J/g°C. If you're specifying the temperature change, you would use the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass of the water (40 g), c is the specific heat capacity of water, and ΔT is the temperature change.
The heat required to boil water can be calculated by multiplying the mass of water (21.1 g) by the specific heat capacity of water (4.18 J/g°C) and the temperature change (100°C - initial temperature). This calculation results in 8.82 kJ or 8820 J of energy needed to boil 21.1 g of water at 100°C.
10ml's of water is equal to 10cm3 of water. 10cm3 of water has a mass of 10g. The specific heat of water is 4.134 J/K. The change in temperature is 1 degree Kelvin. Use Q=mC∆T which means Heat= (Mass)(Specific Heat)(Change in Temperature) Q= (10)(4.134)(1) Q=(10)(4.134) Q=41.34 Joules
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
This value is 22,418 kJ.
The specific heat capacity of water is 4.18 J/g°C. The mass of water is 4000 g. The temperature change is 70.0°C - 0°C = 70.0°C. Therefore, the heat required is 4.18 J/g°C x 4000 g x 70.0°C = 1,170,400 J.
42 J