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The height of the 3 kg object can be determined using the formula for gravitational potential energy: Potential energy = mass x gravity x height. Given that the potential energy is 300 J and the mass is 3 kg, the height can be calculated by rearranging the formula as: Height = potential energy / (mass x gravity). Assuming gravity is approximately 9.81 m/s^2, the object would be approximately 9.71 meters high.
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How high up is a 3 kg objectthat has 300 joules of energy?
The height can be calculated using the potential energy formula PE = mgh, where m is the mass (3 kg), g is the acceleration due to gravity (~9.8 m/s^2), and h is the height. Rearranging the formula, h = PE / (mg). Plugging in the values, h = 300 J / (3 kg * 9.8 m/s^2) ≈ 10 meters.
How high up is a 3.00 kg object that has 300J of energy?
The height can be calculated using the equation: potential energy = mass * gravity * height. Given 300 J of energy and a mass of 3.00 kg, and assuming standard gravity (9.81 m/s^2), the height would be approximately 3.06 meters.
What is the potential energy of a 10.2 kg rock that is sitting on top of a hill that is 300 meters high?
The potential energy of the rock can be calculated using the formula: potential energy = mass × gravity × height. Given the mass of the rock (10.2 kg), the height of the hill (300 meters), and the acceleration due to gravity (approximately 9.81 m/s^2), the potential energy would be 10.2 kg × 9.81 m/s^2 × 300 m = 29970.6 Joules.
Using Einstein's formula if an object has a mass of 300kg what is its energy?
To find the energy of an object using Einstein's formula (E=mc^2), first convert mass from kg to kg (1 kg = 1000 g) and light speed (c) is 3x10^8 m/s. Then, substitute the values into the formula E=mc^2 to calculate the energy. The energy of an object with a mass of 300 kg would be E = 300 kg x (3 x 10^8 m/s)^2.
How fast will an object be moving if its kinetic energy is 300 joules and has a mass of 0.05 kilograms?
To calculate the speed of the object, you can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the speed. Rearrange the formula to solve for v: v = sqrt(2 * KE / m). Plugging in the values given (KE = 300 J and m = 0.05 kg) will give you the speed of the object.
How high up is a 3 kg objectthat has 300 joules of energy?
The height can be calculated using the potential energy formula PE = mgh, where m is the mass (3 kg), g is the acceleration due to gravity (~9.8 m/s^2), and h is the height. Rearranging the formula, h = PE / (mg). Plugging in the values, h = 300 J / (3 kg * 9.8 m/s^2) ≈ 10 meters.
How high up is a 3.00 kg object that has 300J of energy?
The height can be calculated using the equation: potential energy = mass * gravity * height. Given 300 J of energy and a mass of 3.00 kg, and assuming standard gravity (9.81 m/s^2), the height would be approximately 3.06 meters.
What is the potential energy of a 10.2 kg rock that is sitting on top of a hill that is 300 meters high?
The potential energy of the rock can be calculated using the formula: potential energy = mass × gravity × height. Given the mass of the rock (10.2 kg), the height of the hill (300 meters), and the acceleration due to gravity (approximately 9.81 m/s^2), the potential energy would be 10.2 kg × 9.81 m/s^2 × 300 m = 29970.6 Joules.
Using Einstein's formula if an object has a mass of 300kg what is its energy?
To find the energy of an object using Einstein's formula (E=mc^2), first convert mass from kg to kg (1 kg = 1000 g) and light speed (c) is 3x10^8 m/s. Then, substitute the values into the formula E=mc^2 to calculate the energy. The energy of an object with a mass of 300 kg would be E = 300 kg x (3 x 10^8 m/s)^2.
How fast will an object be moving if its kinetic energy is 300 joules and has a mass of 0.05 kilograms?
To calculate the speed of the object, you can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the speed. Rearrange the formula to solve for v: v = sqrt(2 * KE / m). Plugging in the values given (KE = 300 J and m = 0.05 kg) will give you the speed of the object.
What is the momentum of an object that has a mass of 15 kg and a velocity of 20 m per s?
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the momentum of the object would be 300 kg m/s (15 kg * 20 m/s).
How much energy is required to vaporize 1.5 kg of copper?
1650kj
What is the kinetic energy of an object that has a mass of 20 kg and a speed of 2.8m per second?
The object's kinetic energy is 78.4 joules.
What is the potential energy of a ten kg rock that is sitting on a hill that is 300 meters high?
The potential energy of the rock is 29,430 Joules. This is calculated as the product of the mass (10 kg), gravitational acceleration (9.81 m/s^2), and height (300 m) of the rock above the ground. The formula is PE = mgh.
What is the potential energy of a 5 kg object sitting on a shelf 3 m high?
The potential energy of the object is given by the formula: potential energy = mass * gravitational acceleration * height. Plugging in the values: potential energy = 5 kg * 9.8 m/s^2 * 3 m = 147 Joules.
An object with a massof 100 grams (0.100 kg) is dropped from a certain height and has a velocity of 60 meterssecond. If the potential energy of this object is 179.99 joules how high was the object whe?
To calculate the height from which the object was dropped, we need to use the conservation of energy. The potential energy when the object was at the height can be equated to the kinetic energy just before hitting the ground. Potential Energy = Kinetic Energy mgh = 0.5mv^2 Where m = 0.1 kg, g = 9.8 m/s^2, v = 60 m/s Solving for h: h = (0.5 * 0.1 * 60^2) / (0.1 * 9.8) = 183.67 meters.
1000 kg moving 1 m s or 70 kg at 8 m s?
If the question is analyzed by a non-relastivistic approach of the kinetic energy due to the relatively low velocity of the objects, the equation is: K = 0.5mv² where: K: kinetic energy (Joules) m: mass of the object (kg) v: velocity of the object (m/s) The kinetic energy of object 1 at 1000 kg and 1 m/s is: K1 = 0.5(1000kg)(1m/s)² = 500 kg-m/2 = 500 J The kinetic energy of object 2 at 70 kg and 8 m/s is: K2 = 0.5(70kg)(8m/s)² = 2240 J If higher energy is preferable, than select object 2. If lower energy is preferable, than select object1.
